Sulfur-32 Information
This element is absorbed by plants from the soil as sulphate ion. Sulfur has 23 isotopes, 4 of them are stable. Sulfur is used in matches, gunpowder, medicines, rubber and pesticides, dyes and insecticides.
<h3>Which isotope of sulfur contributes the least to its mass number?</h3>
Sulfur (16S) has 23 known isotopes with mass numbers ranging from 27 to 49, four of which are stable: 32S (95.02%), 33S (0.75%), 34S (4.21%), and 36S (0.02%).
<h3>What is the use of Sulphur 35 isotope?</h3>
A radioactive sulfur isotope; a beta emitter with a half-life of 87.2 days; used as a tracer in the study of the metabolism of cysteine, cystine, methionine, and other compounds; also used to estimate, with labeled sulfate, extracellular fluid volumes.
Learn more about isotopes here:
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brainly.com/question/364529</h3><h3 /><h3>#SPJ4</h3>
Answer:
Energy
Explanation:
A sugar group would be used for carbohydrates or nucleic acids. An adenosine group would be used in ATP formation if I recall correct. And disaccharides are just two monosaccharides linked together, so that would also be for carbohydrates. Therefore, energy is the answer.
elements:
calcium : for strong bones
Iron : maintaining haemoglobin for metabolism
compunds
sodium chloride : to maintain blood pressure and other life processes
Adenosine Triphosphate: for metabolism, to maintain rate of inhalation and exhalation of oxygen and to supply energy
Mixture:
I) gasoline : used as fuel
ii) cement : used in construction
Answer:
Protons: 84
Neutrons: 127
Explanation:
The number of protons is the atomic number. The number of neutrons can be found by subtracting the proton number (84) from the isotope number (211)
(4 mol H2O) x (112 kJ / 3 mol H2O) = 149 kJ
<span>(14.5 g HCl) / (36.4611 g HCl/mol) x (112 kJ / 3 mol HCl) = 14.9 kJ </span>
<span>(475 kJ) / (181 kJ / 2 mol HgO) x (216.5894 g HgO/mol) = 1137 g HgO </span>
<span>(179 kJ) / (181 kJ / 1 mol O2) x (31.99886 g O2/mol) = 31.6 g O2 </span>
<span>(145 kJ) / (112 kJ / 3 mol Cl2) x (70.9064 g Cl2/mol) = 275 g Cl2 </span>
<span>(14.5 g S2Cl2) / (135.0360 g S2Cl2/mol) x (112 kJ / 1 mol S2Cl2) = 12.0 kJ </span>
<span>CaCO3 + 2 NH3 → CaCN2 + 3 H2O; ∆H = –90.0 kJ </span>
<span>(798 kJ) / (90.0 kJ / 2 mol HN3) x (17.03056 g NH3/mol) = 302 g NH3 </span>
<span>(19.7 g H2O) / (18.01532 g H2O/mol) x (90.0 kJ / 3 mol H2O) = 32.8 kJ</span>
