Answer:
<h2>Density = 0.2 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
<h3>
</h3>
From the question the points are
mass = 6.8 g
volume = 34 mL
Substitute the values into the above formula and solve
That's
<h3>
</h3>
We have the final answer as
<h3>Density = 0.2 g/mL</h3>
Hope this helps you
It would be B, so yeah hope that helps ya ;)
The value of Q for 125.0 ml of 0.0500 m Pb(NO3)2 is mixed with 75.0 ml of 0.0200 m NaCl at 25°C is 2.11 × 10^(-6).
Aa we know that, 125mL of 0.06M Pb(NO3)2 is mixed with 75.0 ml of 0.0200 m NaCl.
Given, T = 25°C.
<h3>Chemical equation:</h3>
Pb(NO3)2 + NaCl ---- NaNO3 + PbCl2
PbCl2 in aqueous solution split into following ions
PbCl2 ------ Pb(+2) + 2Cl-
Q = [Pb(+2)] [Cl-]^2
The Concentration of Pb(+2) ions and Cl- ions can be calculated as
[Pb(+2)] = 0.06 × 125/200
= 0.0375
[Cl-] = 0.02 × 75/200
= 0.0075
By substituting all the values, we get
[0.0375] [0.0075]^2
= 2.11 × 10^(-6).
Thus, we calculated that the value of Q for 125.0 ml of 0.0500 m Pb(NO3)2 is mixed with 75.0 ml of 0.0200 m NaCl at 25°C is 2.11 × 10^(-6).
learn more about Ions:
brainly.com/question/13692734
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B. False
It was created in 1869
Answer:
The correct answer is option E.
Explanation:
Mass of ferric oxide decomposed = 57.0 g
Moles of ferric oxide decomposed = 
According to reaction, 2 moles ferric oxide on combustion gives 824.2 kJ of heat.
Then heat given by on decomposition of 0.35625 mol of ferric oxide will be:
So, on decomposition of 57.0 grams of ferric oxide 147 kilo Joules of heat was released.
