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3 years ago

Which speed is the fastest?

1 answer:

4 0

<span>A.) 18 feet in 20 minutes
B.) 90 feet in 2.5 hours
C.) 20 yards in 1.5 hours
D.) 3.6 yards in 15 minutes
</span>
A) 18/20=0.9 ft per min
B) 2.5 hours equals 150 minutes . 90/150=0.6 ft per min
C) 20 yds = 60 ft 1.5 hours = 90 minutes 60/90≈0.67 ft per min
D) 3.6 yds = 10.8 ft 10.8/15=0.72

Therefore the fastest would be 0.6 ft per minute therefore, choice
B) 90 feet in 2.5 hours

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There are 20,000 members of a zoo. The percent of

schepotkina [342]

1500 members have a contributor membership.

64.8% of the noncontributory memberships are individual memberships.

<u>Step-by-step explanation:</u>

There are 20,000 members of a zoo.

⇒ Total members = 20,000

From the graph shown,

7.5% of the members have a contributor membership.

<u>To find the number of members who have contributor membership :</u>

⇒ 7.5% of 20,000

⇒ (7.5/100) × 20,000

⇒ 7.5 × 200

⇒ 1500 members.

Therefore, 1500 members have a contributor membership.

<u>To find the percentage of the noncontributory memberships are individual memberships :</u>

The percentage of noncontributory memberships = 100% - 7.5% ⇒ 92.5%

The percentage of individual memberships = 60%

∴ What percentage of the noncontributory memberships are individual memberships ⇒ (60 / 92.5) × 100 = 64.8%

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2 years ago

3. Find the slope of the line that passes through the pair of points.<br> (0, 0), (3,5)

Katena32 [7]

Answer:

5/3

Step-by-step explanation:

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3 years ago

Ments

maw [93]

The sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

<h3>How to find a sector area, and arc length?</h3>

For a sector that has a central angle of θ, and a radius of r;

The sector area, and the arc length are:

$A = \frac{\theta}{360} * \pi r^2$ --- sector area

$L = \frac{\theta}{360} * 2\pi r$ ---- arc length

<h3>How to find the given sector area, and arc length?</h3>

Here, the given parameters are:

Central angle, θ = 160

Radius, r = 5 inches

The sector area is

$A = \frac{\theta}{360} * \pi r^2$

So, we have:

$A = \frac{160}{360} * \frac{22}{7} * 5^2$

Evaluate

A = 34.92

The arc length is:

$L = \frac{\theta}{360} * 2\pi r$

So, we have:

$L = \frac{160}{360} * 2 * \frac{22}{7} * 5$

L = 13.97

Hence, the sector area and the arc length are 34.92 square inches and 13.97 inches, respectively

Read more about sector area and arc length at:

brainly.com/question/2005046

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1 year ago

In figuring his net income, Mr.Halkides listed his salary income of $15,000, $258 from his dividends,and $2562 from the sale of

Black_prince [1.1K]

Net income is all cost factors put together, so total income minus total expenses.

15000 + 258 + 2562 = 17820
1346 + 1598 + 48 = 2992
17820 - 2992 = $14828

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2 years ago

What is the common denominator of -1/y and 2/5y

Anarel [89]

-1/y = 2/5y. The change from -1 to 2 would be -2, so we now that the change from y to 5y would also have to be -2. -2 = -10 so you multiply by 5. After doing the same to the top you would come to the conclusion that the LCD would be 5y. Hope this helps!

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2 years ago