Answer:
amount of work done, W = 549.36 kJ
Given:
mass of a car engine, m = 2500 kg
initial velocity, u = 45 mph
final velocity, v = 65 mph
1 mile = 1609
Solution:
We know that 1 hour = 3600 s
Now, velocities in m/s are given as:
u = 45 mph = = 20.11 m/s
v = 65 mph = = 29.05 m/s
Now, the amount of work done, W is given by the change in kinetic energy of the car and is given by:
W =
W =
W =
W = 549.36 kJ
<span>Chemical and kinetic energy...</span>
The time taken before the two soccer players are 24.7 m apart is 3 seconds.
Velocity of Jane relative to marry is 4.4 m/s in y-direction and 6.95 m/s in x direction.
The distance between Jane and Mary after 4.08 seconds is 33.58 m.
<h3>
Resultant velocity of Mary and Jane</h3>
Vertical component of the velocity;
Jane: Vy1 = V sinθ
Vy1 = 5.07 m/s x sin(60.2)
Vy1 = 4.4 m/s
Horizontal components of the velocity;
Jane: Vx1 = V cos θ
Vx1 = 5.07 m/s x cos60.2
Vx1 = 2.52 m/s
mary: Vx2 = 4.43 m/s
total horizontal components of the velocity = 4.43 m/s + 2.52 m/s = 6.95 m/s
<h3>Resultant velocity</h3>
V = √Vy² + Vx²
V = √(4.4² + 6.95²)
V = 8.23 m/s
<h3>Time taken before they are 24.7 m apart</h3>
t = 24.7 m / 8.23 m/s
t = 3 seconds
Velocity of Jane relative to marry is 4.4 m/s in y-direction and 6.95 m/s in x direction.
<h3>Distance between Jane and Mary after 4.08 seconds</h3>
d = vt
d = 8.23 m/s x 4.08 s
d = 33.58 m
Learn more about relative velocity here: brainly.com/question/17228388
#SPJ1
Distance in a minute=<span>0.5 times 30=15 meters
distance in a second</span><span><span>=15 divided by 60</span>=0.25 meters per second
hope it helps
</span>
Answer:
Explanation:
The funny-looking circle is a hint but iii confirms we are talking about Eartth's magnetic field here :)
i. A is North Pole while H is the magnetic North Pole. D is the equator while C is the magnetic equator.
ii. I, the tilt angle, is about 11 degrees.
iii. A freely suspended magnet inclines towards HF or AG because it always points towards North/South.