Answer:
1. b ∈ B 2. ∀ a ∈ N; 2a ∈ Z 3. N ⊂ Z ⊂ Q ⊂ R 4. J ≤ J⁻¹ : J ∈ Z⁻
Step-by-step explanation:
1. Let b be the number and B be the set, so mathematically, it is written as
b ∈ B.
2. Let a be an element of natural number N and 2a be an even number. Since 2a is in the set of integers Z, we write
∀ a ∈ N; 2a ∈ Z
3. Let N represent the set of natural numbers, Z represent the set of integers, Q represent the set of rational numbers, and R represent the set of rational numbers.
Since each set is a subset of the latter set, we write
N ⊂ Z ⊂ Q ⊂ R .
4. Let J be the negative integer which is an element if negative integers. Let the set of negative integers be represented by Z⁻. Since J is less than or equal to its inverse, we write
J ≤ J⁻¹ : J ∈ Z⁻
Answer:
X=3
Step-by-step explanation:
12+2x=6x
Answer:
(–3, –4)
Step-by-step explanation:
Given pair of linear equation
-4x+y = 8
=> y = 8 + 4x _____(1)
x - 5y = 17 (2)
substituting value of y from equation 1 in equation 2 we have
x - 5(8 + 4x) = 17
=> x - 5*8 -5*4x = 17
=> x - 40 - 20x = 17
=> -40 - 19x = 17
=> -19x = 17+40 = 57
=> x = 57/-19 = -3
Thus, x = -3
y = 8 + 4x = 8 +4(-3) = 8 -12 = -4
Thus, y = -4
Hence, paired solution for given equation is (–3, –4).