Answer:
Yes, it is a function
Step-by-step explanation:
Every possible input x value is paired with a unique output y value.
Another approach is to graph the function then conduct the VLT (vertical line test) at which point you will realize that any vertical line will intersect the graph at one point only meaning it is a function.
Hope this helps.
The first one. Hope this helps
Be glad to tell me if it’s correct or not
Answer:
y = 9.8995
Step-by-step explanation:
This question requires the use of basic trigonometry.
In this problem, we know one of the sides and two of the angles.
Since one of the angles is 45 degrees and the sum of all internal angles of a triangle is 180 degrees, the other angle can only be 45 degrees, making this an isosceles triangle - that is, the length of the other leg, x, is also 7.
You could use the soh cah toa mnemonic to figure it out, but here just using the a^2 + b^2 = c^2 should be sufficient since we know both legs of the triangle.
7^2 + 7^2 = 98, and the square root of 98 gives you about 9.8995, which sounds about right for this situation.
Hope this helped!
The slope of the line passing the points (1, 1) and (0, 0) is 1
<h3>Slope of a line</h3>
The formula for calculating the slope of a line is expressed as
Slope = y2-y1/x2-x1
Given the coordinate points (1, 1) and (0, 0)
Substitute the given coordinate points
Slope = 0-1/0-1
Slope = -1/-1
Slope =1
Hence the slope of the line passing the points (1, 1) and (0, 0) is 1
Learn more on slope of a line here: brainly.com/question/3493733
#SPJ1
Answer:
Explanation:
The function that represents the number of E.coli bacteria cells per 100 mL of water as the time t years elapses is:
The base, 1.123, represents the multiplicative constant rate of change of the function, so you just must substitute 1 for t in the power part of the function:
Then, the multiplicative rate of change is 1.590, which means that every year the number of E.coli bacteria cells per 100 mL of water increases by a factor of 1.590, and that is 1.59 - 1 = 0.590 or 59% increase.