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2 years ago

Will give brainlist to who finds this out!

Mathematics

2 answers:

castortr0y [4]2 years ago

8 0

Answer:

Step-by-step explanation:

Sav [38]2 years ago

7 0

Answer:

$\sqrt{1}, \sqrt{4}, \sqrt{9}$

Step-by-step explanation:

First, remember that rational numbers either terminate or have repeating decimals. Those three are the only answers with perfect squares, $\sqrt{1} = 1, \sqrt{4} = 2, \sqrt{9} = 3$ . As you can see all of these answers terminate and therefore are rational, the rest go one forever while never repeating.

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( First 5 questions. ) Which of the following ordered pairs is a solution of the given system of linear equations?

Mrac [35]

1. (3,-2)

2. (-5,-4)

3. (-20,11)

4. (2,3)

5. (13/7, 40/7)

6 0

2 years ago

Abigail's and gina's ages are consecutive integers. abigail is younger than gina and gina's age is represented by x. if the diff

Ostrovityanka [42]

If Gina's age is x and Abigail is younger than Gina, Abigail's age will be represented by x-1 given that their ages are consecutive integers.

Translating the fact that the the difference of the square of Gina's age and eight times Abigail's age is 17, we will have the following equation:

$x^{2} -8(x-1)=17$

We can use the equation above to find Gina's age.

4 0

2 years ago

What is the factorization of 729^15+1000?

igomit [66]

Answer:

The factorization of $729x^{15} +1000$ is $(9x^{5} +10)(81x^{10} -90x^{5} +100)$

Step-by-step explanation:

This is a case of factorization by sum and difference of cubes, this type of factorization applies only in binomials of the form $(a^{3} +b^{3} )$ or $(a^{3} -b^{3})$ . It is easy to recognize because the coefficients of the terms are perfect cube numbers (which means numbers that have exact cubic root, such as 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.) and the exponents of the letters a and b are multiples of three (such as 3, 6, 9, 12, 15, 18, etc.).

Let's solve the factorization of $729x^{15} +1000$ by using the sum and difference of cubes factorization.

1.) We calculate the cubic root of each term in the equation $729x^{15} +1000$ , and the exponent of the letter x is divided by 3.

$\sqrt[3]{729x^{15}} =9x^{5}$

$1000=10^{3}$ then $\sqrt[3]{10^{3}} =10$

So, we got that

$729x^{15} +1000=(9x^{5})^{3} + (10)^{3}$ which has the form of $(a^{3} +b^{3} )$ which means is a sum of cubes.

Sum of cubes

$(a^{3} +b^{3} )=(a+b)(a^{2} -ab+b^{2})$

with $a= 9x^{5}$ y $b=10$

2.) Solving the sum of cubes.

$(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)((9x^{5})^{2}-(9x^{5})(10)+10^{2} )$

$(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)(81x^{10}-90x^{5}+100)$

8 0

2 years ago

You collect a total of $75 in donations from three people. The three donations are in the ratio 4 to 4 to 7. How much is each of

worty [1.4K]

Each smaller donation was for $20 The largest donation was $15 greater than the smaller donation. First, determine the size of each donation. Since they are in a ratio of 4:4:7, it's easiest to add the ratios together (4+4+7) = 15. Then divide the total donation by that sum (75/15) = 5. Finally, multiply 5 by each of the ratios. 5 * 4 = 20, 5 * 4 = 20, and 5 * 7 = 35 So the 2 smaller donations were $20 each, and the largest donation was for $35. The largest donation was $35 - $20 = $15 larger than one of the smaller donations.

7 0

2 years ago

Helpppp pls. Rotate traingle TUV 90 degrees clockwise around the origin

lutik1710 [3]

T -1,-1 ect ect hope helps

7 0

1 year ago