Answer:
40
Step-by-step explanation:
6 of 30 is the ratio 6 to 30 or 6/30.
6/30 reduces to 1/5
The survey shows that 1/5 of the students attend summer camp.
1/5 of 200 = 1/5 * 200 = 40
Answer:
The volume of foam needed to fill the box is approximately 2926.1 cubic inches.
Step-by-step explanation:
To calculate the amount of foaming that is needed to fill the rest of the box we first need to calculate the volume of the box and the volume of the ball. Since the box is cubic it's volume is given by the formula below, while the formula for the basketball, a sphere, is also shown.
Vcube = a³
Vsphere = (4*pi*r³)/3
Where a is the side of the box and r is the radius of the box. The radius is half of the diameter. Applying the data from the problem to the expressions, we have:
Vcube = 15³ = 3375 cubic inches
Vsphere = (4*pi*(9.5/2)³)/3 = 448.921
The volume of foam there is needed to complete the box is the subtraction between the two volumes above:
Vfoam = Vcube - Vsphere = 3375 - 448.921 = 2926.079 cubic inches
The volume of foam needed to fill the box is approximately 2926.1 cubic inches.
Hello!!
2^y = log(66)/log(9)
y = log(log(66)/log(9))/ log(2)
Good luck :)
Step-by-step explanation:
Ques 1)
abc: 15 = 16 rest 1
that means that if abc is divided by 15 than we get the quotient as 16 and remainder as 1.
Hence using : dividend=divisor×quotient+remainder we have:
abc=15×16+1
Hence, the value of abc is 241.
Ques 2)
a)
486: x = 17
i.e.
⇒ x=486×17=8262
b)
y: 18 = 35 rest 1
that means when y is divided by 18 we get the quotient as 35 and remainder as 1.
Hence using : dividend=divisor×quotient+remainder we have:
y=35×18+1=631
y=631
c)
730: z = 27 rest 1
that means when 730 is divided by z we get the quotient as 27 and remainder as 1.
Hence using : dividend=divisor×quotient+remainder we have:
730=27z+1
27z=730-1
27z=729
z=27 (dividing both side by 27)
Ques 3)
Let'a' and 'b' denote the two natural numbers such that a is greater than 'b'.
a-b=70----(1)
also when a is divided by b then we get the quotient as 8 and some remainder.
Let the remainder be 'r'.
this means a=8b+r
let us consider r=0.
a=8b
hence from (1) we have
7b=70
b=10 (on dividing both side by 7)
hence a=80.
when r=1,2,3,4,5,6
we do not get a natural number as value for a and b.
also when r=7 we get the value of b=9 and a=79
After r>7 we get the value of b<r such a condition is not possible.