Answer:
24) A
22) B
Step-by-step explanation:
24)
Original Price: d
Sale: 30%
A sale means that a value is subtracted from the original price
d - 30% = 0.7d
All options given:
A) 0.3d
B) 0.7d
C) d - 0.3d = 0.7d
D) (1.0 - 0.3)d = 0.7(d) = 0.7d
All of these options are equal to the price after the sale, except A.
A is the answer to question 24
22) m > 0, n > 0 Use an example to represent m and n
m = 1, n = 2 = -0.5
-0.5 is a rational, negative number
The answer to question 22 is B
Hope this helps :)
Answer in fraction form is 1/3
Answer in decimal form is 0.3333
Pick one answer only.
==========================================================
Explanation:
The sample space is the set of all possible outcomes. In this case, the outcomes consist of values between 1 and 6
S = sample space
S = {1,2,3,4,5,6}
There are 6 items here. Let B = 6.
We want to roll a number greater than 4, so the event space we're after is
E = {5,6}
which consists of 2 items. Let A = 2.
The probability we want is A/B = 2/6 = 1/3 = 0.3333
So if you go with the fraction option, then you'll type in 1/3
If you go with the decimal option, then you'll type in 0.3333
Answer:
That day 51 child tikets were sold
Step-by-step explanation:
To do this problem we have to make 2 equations, one that represents the number of entries and the other that represents the money
x = child tickets
y = adult tickets
x + y = 132
x * $5.20 + y * $9.00 = $994.20
First we have to solve for the x in the first equation
x + y = 132
x = 132 - y
Now we replace the x with (132 - y) in the second equation
x * $5.20 + y * $9.00 = $994.20
(132 - y) * 5.20 + y * 9.00 = 994.20
686.4 - 5.2y + 9y = 994.2
-5.2y + 9y = 994.2 - 686.4
3.8y = 307.8
y = 307.8/3.8
y = 81
We replace y with its value in the first equation
x = 132 - y
x = 132 - 81
x = 51
That day 51 child tikets were sold
Answer:
All sides will be 11 and all angles will be 90 degrees.
Step-by-step explanation:
As all sides of square are equal. And all angles are right angled.
Hope it helped!!
Check the picture below.
well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.
bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.
![\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}](https://tex.z-dn.net/?f=%5Cbf%20A%28%5Cstackrel%7Bx_1%7D%7B1%7D~%2C~%5Cstackrel%7By_1%7D%7B4%7D%29%5Cqquad%20B%28%5Cstackrel%7Bx_2%7D%7B5%7D~%2C~%5Cstackrel%7By_2%7D%7B1%7D%29%20~%5Chfill%20%5Cstackrel%7Bslope%7D%7Bm%7D%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%20%7B%5Cstackrel%7By_2%7D%7B1%7D-%5Cstackrel%7By1%7D%7B4%7D%7D%7D%7B%5Cunderset%7Brun%7D%20%7B%5Cunderset%7Bx_2%7D%7B5%7D-%5Cunderset%7Bx_1%7D%7B1%7D%7D%7D%5Cimplies%20%5Ccfrac%7B-3%7D%7B4%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bslope%20of%20AB%7D%7D%7B-%5Ccfrac%7B3%7D%7B4%7D%7D%5Cqquad%20%5Cqquad%20%5Cqquad%20%5Cstackrel%7B%5Ctextit%7B%5Cunderline%7Bnegative%20reciprocal%7D%20and%20slope%20of%20the%20diameter%7D%7D%7B%5Ccfrac%7B4%7D%7B3%7D%7D)
so, it passes through the midpoint of AB,
so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)
