Answer:
<h2>absolute maximum = 16</h2><h2>absolute minimum = 1</h2>
Step-by-step explanation:
To get the absolute maximum and minimum values of the function f(x) = 16 + 2x − x² n the given interval [0,5], we need to get the values of f(x) at the end points. The end points are 0 and 5.
at x = 0;
f(0) = 16 + 2(0) − 0²
f(0) = 16
at the other end point i.e at x = 5;
f(5) = 16 + 2(5) − 5²
f(5) = 16 + 10-25
f(5)= 26-25
f(5) = 1
The absolute minimum value is 1 and occurs at x = 5
The absolute maximum value is 16 and occurs at x = 0
9 3/4 = 39/4 mi/m
68 1/4 = 273/4 min
39/4 mutiply by 273/4 = 10647 / 16 mi = 665.4 mi
Answer:
<h2>Net proceed= s-0.98nd-11</h2>
Step-by-step explanation:
Given that the shares cost $d
n shares will be =$dn
paid 2% commission to her broker= (2/100)*nd= 0.02nd
sold the share for $s
paid a fee of $11
Her net proceeds algebraically will be
Net proceed= s-nd-11-0.02nd
collect like terms
Net proceed= s-(nd-0.02nd)-11
Net proceed= s-0.98nd-11
0.018 will be 18/1000 = 9/500
