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2 years ago

6

To prepare for school you need 3 notebooks for $1.09 each, 2 boxes of pencils for $2.68 each and a pack of markers for $0.89. Ho

w much will this cost?
ASAP ill give brainliest

1 answer:

Iteru [2.4K]2 years ago

3 0

Answer:

$9.52

Step-by-step explanation:

1.09 x 3 = 3.27

2.68 x 2 = 5.36

3.27+5.36+.89=9.52

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For what values of $x$ is $$\frac{x^2 + x + 3}{2x^2 + x - 6} \ge 0?$$ note: be thorough and explain why all points in your answe

Rus_ich [418]

To solve the inequality $\frac{x^2+x+3}{2x^2+x-6}\ge \:0$

$\mathrm{Factor\:the\:left\:hand\:side\:}\frac{x^2+x+3}{2x^2+x-6}:$

The numerator $x^2+x+3$ is not factorizable.

so factor the denominator $2x^2+x-6$ :

$2x^2+x-6=\left(2x^2-3x\right)+\left(4x-6\right)=x\left(2x-3\right)+2\left(2x-3\right)\\ \mathrm{Factor\:out\:}x\mathrm{\:from\:}2x^2-3x\mathrm{:\quad }x\left(2x-3\right)\\ \mathrm{Factor\:out\:}2\mathrm{\:from\:}4x-6\mathrm{:\quad }2\left(2x-3\right)\\$

Now take $\mathrm{Factor\:out\:common\:term\:}\left(2x-3\right)$

Then we get factor of the denominator as $\left(2x-3\right)\left(x+2\right)$

Thus $\frac{x^2+x+3}{2x^2+x-6}=\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}$

Now $\mathrm{Compute\:the\:signs\:of\:the\:factors\:of\:}\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}\\$

Signs of $x^2+x+3>0$

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$x\frac{3}{2}$ is the required solution of the given inequality.

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Step-by-step explanation:

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2 years ago

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Looking at the diagram,

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Width = 4 cm

Height = 2 cm

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m_a_m_a [10]

Answer:

$A_{shape}=A_{triangle}+A_{square}\\\\A_{shape}=(\frac{bh}{2}+s^2)\ units^2$

Step-by-step explanation:

I assume that it is a composed figure formed by a triangle and a square.Since you did not give the dimensions of the triangle and the dimensions of the square, I will giveyou a general explanation about how to solve this exercise.

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$A_{square}=s^2$

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