Gel electrophoresis is a method of genetic analysis which involves seperating segments of DNA based on their size and charge.
It involves cutting DNA with various enzymes, then placing the DNA in an agarose gel. An electrical current is then run through the gel. Because DNA is a polar molecule the DNA segments will travel through the agarose cell as the current is applied. Larger fragments will travel shorter distances than shorter fragments. Two plates with 2 different DNA samples will be conducted and the orientation of the DNA strands will be used to make an analysis by comparing the 2 plates.
The answer is A. Man-made
Answer:
A: Unlike DNA, XNA replicates conservatively
Explanation:
<em>The replication of the DNA is </em><em>semi conservative.</em><em> This means that newly replicated double helix DNAs usually consist of one parental strands and one newly synthesized strands. The parental DNA unwinds and each strand serves as template for the synthesis of complementary strands.</em>
In the case of XNA, the two strands of parental XNA were found intact, meaning that the newly produced XNA consist of two newly synthesized strands. This thus means that the replication process is conservative.
Hence, unlike DNA replication that is semi conservative, XNA replication is conservative.
Complete question:
Suppose "A" is a dominant gene for the ability to taste phenylthiocarbamide and "a" is a recessive gene for the inability to taste it. Which couples could possibly have both a child who tastes it and a child who does not?
a. father AA, mother aa
b. father Aa, mother AA
c. father Aa, mother Aa
d. father AA, mother AA
Answer:
c. father Aa, mother Aa
Explanation:
According to the given information, the ability to taste phenylthiocarbamide is a dominant trait and is imparted by the allele "A". This phenotype would be expressed in both homozygous and heterozygous conditions. The non-taster phenotype would be expressed in the homozygous recessive genotypes only.
To have both taster and non-taster children, both the parents should have at least one copy of the recessive allele. Among the given options, the father with genotype Aa and the mother with genotype Aa have the possibility to have both taster and non-taster children.
Aa x Aa= 3/4 taster (1/4 AA and 1/2 Aa): 1/4 non-taster (1/4 aa)