Maria isn't correct of this. Adding these will get you 82960 (You add the numbers) She must have miscalculated.
The answer is 24/35. i would tell you to simplify but it is already in its simpliest form.
Answer: have you tried to use photomath?
Answer:
P(B|A)=0.25 , P(A|B) =0.5
Step-by-step explanation:
The question provides the following data:
P(A)= 0.8
P(B)= 0.4
P(A∩B) = 0.2
Since the question does not mention which of the conditional probabilities need to be found out, I will show the working to calculate both of them.
To calculate the probability that event B will occur given that A has already occurred (P(B|A) is read as the probability of event B given A) can be calculated as:
P(B|A) = P(A∩B)/P(A)
= (0.2) / (0.8)
P(B|A)=0.25
To calculate the probability that event A will occur given that B has already occurred (P(A|B) is read as the probability of event A given B) can be calculated as:
P(A|B) = P(A∩B)/P(B)
= (0.2)/(0.4)
P(A|B) =0.5
Answer:
32
Step-by-step explanation:
(-8 × -6) - 4²
48 - 4²
48 - 16 = 32
P - Parentheses
E - Exponents
M - Multiplication
D - Division
A - Addition
S - Subtraction
