Am I correct? I put

Andrew's math teacher entered the seventh grade students in a math competition there was an enrollment fee of $30 and also an $1

N76 [4]

Answer: 110

Step-by-step explanation:

Given;

Total cost C = $151

Enrollment fee E = $30

Charge per 10 test t = $11

n is the number of packet of test taken.

The questions can be represented by the equation below;

30 + 11n = 151

Substracting 30 from both sides.

11n = 151-30 = 121

n = 121/11

n = 11

Since the number of packet of test is 11 and each packet contains 10 tests. The number of test N is given by;

N = 10 n = 10 ×11 = 110

N = 110

5 0

2 years ago

The mean height of a group of 500 nonsmoking college students is 74 inches and the standard deviation is 5 inches. What is the p

Brrunno [24]

500 (non smokers)÷ 25(random students out of the group)= 20 inches. 20 inches ÷ 74 inches= 3.70

3 0

2 years ago

‍♀️ can someone help

Dmitriy789 [7]

Answer:

the answer should be 5/16

5 0

3 years ago

Write the equation in slope-intercept form through the point (-4, -7) and is perpendicular to the line y = -(7/4)x + 4 and graph

Scilla [17]

You have to write the equation for a line that crosses the point (-4, -7) and is perpendicular to the line

$y=-\frac{7}{4}x+4$

When you have to determine a line that is perpendicular to a known line, you have to keep in mind that the slope of the perpendicular line will be the negative inverse of the first one.

If for exampla you have two lines, the first one being:

$y_1=mx+b$

And the second one, that is perpedicular to the one above:

$y_2=nx+c$

The slope of the second one is the negative inverse of the first one:

$n=-\frac{1}{m}$

The slope of the given line y=-7/4+4 is m=-7/4

So the slope of the perpendicular line has to ve the inverse negative of -7/4

$\begin{gathered} n=-(-\frac{4}{7}) \\ n=\frac{4}{7} \end{gathered}$

Considering it has to pass through the point (-4,-7) and that we already determined its slope, you can unse the point slope formula to determine the equation of the perpendicular line:

$y-y_1=m(x-x_1)$

replace with the coordinates of the point and the slope and calculate:

$\begin{gathered} y-(-7)=\frac{4}{7}(x-(-4)) \\ y+7=\frac{4}{7}(x+4) \\ y+7=\frac{4}{7}x+\frac{16}{7} \end{gathered}$

Subtract 7 to both sides of the equation to write it in slope-intercept form:

$\begin{gathered} y+7-7=\frac{4}{7}x+\frac{16}{7}-7 \\ y=\frac{4}{7}x-\frac{33}{7} \end{gathered}$

Now you can graph both lines

8 0

7 months ago

An estimated regression equation that was fit to estimate ductility in steel using its carbon content was found to be significan

AnnZ [28]

Answer:

At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.

Step-by-step explanation:

Hello!

Considering the dependent variable:

Y: Ductility in steel.

And the independent variable:

X: Carbon content of the steel.

The linear regression was estimated and a prediction interval was calculated.

The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X= $x_{0}$ ]

In this case 95% prediction interval for Y/X=0.5

At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.

I hope it helps!

6 0

2 years ago