Answer:
Hey mate, here is your answer. Hope it helps you.
Explanation:
The balanced equation is 2Na+2H2O———-> 2NaOH +H2.
Answer:
Explanation:
Hello,
In this case, the chemical reaction is:
Thus, we first identify the limiting reactant by computing the yielded moles of water by both of the reactants:
In such a way, since HBr yields less water than cadmium hydroxide, we infer that HBr is the limiting one, therefore, the yielded mass of water are:
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Answer:
Mass of compound = 0.24 g and, mass of boron = 0.096 g percentage of boron in the compound = mass of boron / mass of compound * 100 = 0.096/0.24 * 100 = 40% mass of oxygen = 0.144 g again, mass of compound = 0.24 g percentage of oxygen in compound = mass of oxygen/mass of of compound * 100 = 0.144/0.24 * 100 = 60%
<h2>Hope it's Helpful!!✌️</h2>
The color change of a pH indicator is caused by the dissociation of the H+ ion from the indicator.
<h3 /><h3>What is indicator?</h3>
In science, a marker capability or a trademark capability of a subset An of a set X is a capability characterized from X to the two components set {0, 1}, normally signified as, and it demonstrates whether a component in X has a place with A. Markers are insights used to gauge current circumstances as well as to figure monetary or financial patterns. In the realm of money management, pointers regularly allude to specialized diagram designs getting from the value, volume, or open revenue of a given security. Markers are insights used to gauge current circumstances as well as to conjecture monetary or financial patterns. In the realm of money management, pointers normally allude to specialized graph designs getting from the value, volume, or open revenue of a given security.
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Answer:
% (COOK)2H2O = 37.826 %
Explanation:
mix: (COOK)2H2O + Ca(OH)2 → CaC2O4 + H2O
∴ mass mix = 4.00 g
∴ mass (CaC2O4)H2O = 1.20 g
∴ Mw (COOK)2H2O = 184.24 g/mol
∴ Mw (CaC2O4)H2O = 146.12 g/mol
∴ r = mol (COOK)2H2O / mol (CaC2O4)H2O = 1
- % (COOK)2H2O = (mass (COOK)2H2O / mass Mix) × 100
⇒ mass (COOK)2H2O = (1.20 g (CaC2O4)H2O)×(mol (CaC2O4)H2O / 146.12 g (CaC2O4)H2O)×(mol (COOK)2H2O/mol (CaC2O4)H2O)×(184.24 g (COOK)2H2O/mol (COOK)2H2O)
⇒ mass (COOK)2H2O = 1.513 g
⇒ % (COOK)2H2O = ( 1.513 g / 4 g )×100
⇒ % (COOK)2H2O = 37.826 %