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2 years ago

Can anyone help! WITH STEPS!

Mathematics

1 answer:

MissTica2 years ago

6 0

Answer:

When we have something like:

$\sqrt[n]{x}$

It is called the n-th root of x.

Where x is called the radicand, and n is called the index.

Then the term:

$\sqrt[4]{16}$

is called the fourth root of 16.

And in this case, we can see that the index is 4, and the radicand is 16.

At the end, we have the question: what is the 4th root of 16?

this is:

$\sqrt[4]{16} = \sqrt[4]{4*4} = \sqrt[4]{2*2*2*2} = 2$

The 4th root of 16 is equal to 2.

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Find the twenty-fifth term of an arithmetic sequence if the first term is-1 and the common difference is 5. Write the first thre

denis-greek [22]

Answer:

1). $T_{25}=119$

2). $T_{1}=-23$

$T_{2}=-23+2=-21$

$T_{3}=-23+4=-19$

Step-by-step explanation:

First term of an arithmetic sequence is (-1) and common difference is 5.

Then we have to find twenty fifth term of this arithmetic sequence.

Since explicit formula of an arithmetic sequence is represented by

$T_{n}=a+(n-1)d$

Where $T_{n}$ represents nth term of the sequence.

a = first term

n = number of term

and d = common difference

Now we will find 25th term of this sequence.

$T_{25}=(-1)+(25-1)5$

= (-1) + 120

= 119

Similarly in second part of this question we have to find first three terms of an arithmetic sequence in which

$T_{21}=17$ and

$T_{50}=75$

Now from the explicit formula

17 = a + (21 - 1)d

17 = a + 20d --------(1)

75 = a + (50 - 1)d

75 = a + 49d --------(2)

Now we subtract equation 1 from 2

75 - 17 = 49d - 20d

29d = 58

d = $\frac{58}{29}=2$

By putting d = 2 in equation 1

17 = a + 20×2

17 = a + 40

a = 17 - 40

a = -23

Therefore, first three terms of this sequence will be

$T_{1}=-23$

$T_{2}=-23+2=-21$

$T_{3}=-23+4=-19$

8 0

2 years ago

Pythagorean Theorem with Known Legs

IgorC [24]

Answer:

$\sqrt{170} = c$

Step-by-step explanation:

We are trying to find the hypotenuse of a right triangle

We will use the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

11^2 + 7^2 = c^2

121 + 49 = c^2

170 = c^2

Taking the square root of each side

$\sqrt{170} = c$

5 0

1 year ago

Read 2 more answers

Add the equation u-v/8v + 6u-3v/8v

notka56 [123]

Answer:

7u-4v/8

Step-by-step explanation:

u+6u=7u

-v+(-3v)=-v-3v=-4v

7u-4u/8

8 0

2 years ago

What is the angle, in radians, of arcsin(1/2)

ki77a [65]

$\frac{\pi}{6}$

When you are asked what is the sin of π/6, or 30 degrees, you would look at the special triangle (30-60-90) to see that sin, or opposite over hypotenuse, of π/6 is 1/2. Arcsin, or csc, will present you with the ratio, 1/2, and ask for the angle. It's essentially working the question backwards.

6 0

2 years ago

Abe is 7 inches taller than Chen.

MrMuchimi

Answer:

The sum of h and 7

Step-by-step explanation:

If Abe is 7 inches taller than Chen, and Chen is h inches, then Abe's height is equal to 7+h.

3 0

2 years ago