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2 years ago

PLEASE HELP ME

Mathematics

2 answers:

KatRina [158]2 years ago

6 0

0.8917
.......................

patriot [66]2 years ago

5 0

What grade jeiiieudhwhwjskjewhehkzbzvdvs

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in which place is the digit in the numbers 5,341 that would be changed to form 5,841? how do the values of the two numbers compa

Akimi4 [234]

The changed digit is the third to the left of the decimal point, so is in the hundreds place.

The value of 8 hundred is 5 hundred more than the value of 3 hundred. The second number is 500 more than the first.

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2 years ago

Find the unit rate. <br> 247 heartbeats in 612 minutes

ollegr [7]

Answer:

247/612 bpm

Step-by-step explanation:

247 beats / 612 minutes

beats / minute

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2 years ago

Find and simplify the quotient 2/3 divided by 8/9

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2 years ago

Write an inequality for x that would give this rectangle a perimeter of at least 300ft

Travka [436]

Answer:

The inequality for $x$ is:

$x\geq 142$

Step-by-step explanation:

Given:

Width of rectangle = 3 ft

Height or length of rectangle = $(x+5)$ ft

Perimeter is at least 300 ft

To write an inequality for $x$ .

Solution:

Perimeter of a rectangle is given as:

⇒ $2l+2w$

where $l$ represents length of the rectangle and $w$ represents the width of the rectangle.

Plugging in the given values in the formula, the perimeter can be given as:

⇒ $2(x+5)+2(3)$

Using distribution:

⇒ $2x+10+6$

Simplifying.

⇒ $2x+16$

The perimeter is at lest 300 ft. So, the inequality can be given as:

⇒ $2x+16\geq 300$

Solving for $x$

Subtracting both sides by 16.

⇒ $2x+16-16\geq 300-16$

⇒ $2x\geq284$

Dividing both sides by 2.

⇒ $\frac{2x}{2}\geq \frac{284}{2}$

⇒ $x\geq 142$ (Answer)

7 0

2 years ago

An initial of the $100 is now valuated at $150. The annual interest rate is 5%, compounded continuously. The equation 100e^0.05=

tangare [24]

Answer:

8 years approximately

The problem (I'm assuming is):

Solve $100e^{0.05t}=150$ .

I put a t in the problem where I suspected it in went.

Step-by-step explanation:

$100e^{0.05t}=150$

Divide both sides by 100:

$e^{0.05t}=\frac{150}{100}$

$e^{0.05t}=1.5$

Rewrite in logarithm form.

$\ln(1.5)=0.05t$

Divide both sides by 0.05:

$\frac{\ln(1.5)}{0.05}=t$

Put left hand side into calculator:

$8.109 \approx t$

$t \approx 8.109$

So about 8 years if I wrote down the equation correctly.

4 0

2 years ago

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