P = 300/V
Because in order to isolate P, you have to divide V on both sides.
You found CD from the Pythagorean theorem to be ...
... CD = √(5² -2²) = √21
Since triangle ADC ~ triangle ACB, the ratios of corresponding sides are the same:
... AC/AD = AB/AC
... AB = AC²/AD
... AB = 5²/2 = 12.5 . . . . . . . the base of the overall triangle
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Then the area (A) is ...
... A = (1/2)bh
... A = (1/2)(12.5)(√21) ≈ 28.64 square units
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As you see here, the altitude of a right triangle divides it into three similar triangles. From smallest to largest, they are ...
... ADC ~ CDB ~ ACB
You can figure this using AAA similarity, since the smallest and largest triangles listed above share an acute angle vertex (∠A). That, together with the right angle, means all angles are congruent. After that, then you know ∠ACD ≅ ∠CBD, so you can show the middle sized triangle is similar to the other two.
For the answer to the question above, I'll show my solution for the answer below.
Area A = pi r^2
<span>The rate of change of area = d A/ d t = 2 pi r d r/d t </span>
<span>r= 2t, d r = 2 d t </span>
<span>This gives </span>
<span>d A/ d t = 2 pi 2t 2 d t = 8 pi t dt </span>
<span>Integrate it </span>
<span>A= 4 pi t^2. </span>
<span>After t=5, the area will be 100* 3.14 square= 314 square units.</span>
Answer:
(D) 30 degrees
Step-by-step explanation:
An inscribed angle is an angle formed by two chords in a circle which have a common endpoint.
<u>Theorem(Inscribed Angles Conjecture I): </u>In a circle, the measure of an inscribed angle is half the measure of the central angle with the same intercepted arc.
By the theorem above and from the attached diagram,
Inscribed Angle p =Half of 60 degrees
<u>The correct option is D.</u>
The last one would be incorrect. We are looking for PART of whatever N is. Multiply by the whole number 25 is definitely not what we want to do.
Hope I helped!
