It is the first statement. It is positive two, so it’s above sea level. We can immediately get rid of the last two statements. Then, it is negative 20. The is 18 feet below sea level, because 2-20 is -18. Positive 8 shows rising up by 8 feet. The correct statement is the first one.
The rate of change is 16.8 million tons per year
<em><u>Solution:</u></em>
Given that, the world catch of fish in 1950 was 12 million tons and in 1955 it was 96 million tons
<em><u>The average rate of change is given by formula:</u></em>
Value in 1950 = 12 million tons
Value in 1955 = 96 million tons
Change in value = value in 1955 - value in 1950
Change in value = 96 million - 12 million = 84 million tons
Number of years = 1950 to 1955 = 5 years
<em><u>Substitute the given values in formula,</u></em>
<em><u></u></em>
<em><u></u></em>
Thus rate of change is 16.8 million tons per year
Answer:
The way to answer this question is to find out the price per pound potato by dividing the amount the restaurant chief paid by the number of pounds bought.
Your question lacks details on the pounds bought in the other stores so I will assume these figures and you can use it as a reference.
Restaurant B - 2 pounds
Restaurant C - 12 pounds
Restaurant D - 5 pounds
Price per pound
Restaurant A = 6.60/8
= $0.83
Restaurant B = 3.50/2
= $1.75
Restaurant C = 9.75/12
= $0.82
Restaurant D = 4.80/8
= $0.96
<u><em>Restaurant C </em></u><em>has the lowest price per pound for potatoes. </em>
The number 1.04 represents the rate at which the house appreciates, or increases in its price annually.
As according to the values of an exponential equation, which is represented by this: y=ab^x, the a value represents the original price, the b value represents the rate of growth/decay (if growth, you add 1 to the rate, if decay, you subtract the rate from 1), and x represents the amount of times it decays or grows.
As according to the function <span> f(x) = 242,000(1.04)^x, 242,000 is the original price and 1.04 is the rate of growth since 1 has been added to the the 4% annual growth.</span>
