Answer:
5.09 x 10⁵ Nm²/C
Explanation:
The electric flux φ through a planar area is defined as the electric field Ε times the component of the area Α perpendicular to the field. i.e
φ = E A
From the question;
E = (8.0j + 2.0k) ✕ 10³ N/C
r = radius of the circular area = 9.0m
A = area of a circle = π r² [Take π = 3.142]
A = 3.142 x 9² = 254.502m²
Now, since the area lies in the x-y plane, only the z-component of the electric field is responsible for the electric flux through the circular area.
Therefore;
φ = (2.0) x 10³ x 254.502
φ = 5.09 x 10⁵ Nm²/C
The electric flux is 5.09 x 10⁵ Nm²/C
Answer:
Due to lower risk of injury or damage.
Explanation:
The high divers would choose to enter the water from the feet first because there is low risk of injury. The brain is the most important part of the body which very sensitive to any small injury. Small injury to brain leads to big problems in life. High divers can reach speeds of nearly 60 mph and enters about 28m into the water in about three seconds which can damage the head region if comes in contact with the ground so this is the reason the high divers avoid of entering in the water through their heads and choose entering through their feet.
Answer:
If jack is in the piece of furniture it would submerge.
Explanation:
The piece of furniture would submerge if the weight applied on the furniture is greater than the maximum buoancy force the water can provide.
maximum buoacy force = density of liquid × volume submerged× acceleration due to gravity.
=
v = area × thickness of pine
= 0.075
therefore buoancy force = 1025×0.075×9.8 N
= 753.375 N
weight of rose alone = 46×9.8 N = 450.8 N
weight of jack alone = 58×9.8 = 568.4 N
weight of pine = density of pine × volume of pine
= 350 × 0.075= 26.25 N
weight of pine + weight of rose = 450.8+26.25=477.05 N
weight of pine + rose + jack = 477.05 + 568.4 = 1045.45 N
therefore if jack is in the piece of furniture it would submerge.
The apparent depth of an object at the bottom of a tank filled with a liquid of refractive index 1.3 is 7.7 cm. What is the actual depth of the liquid in the tank?
REFRACTIVE INDEX = 1.3
APPARENT DEPTH = 7.7 cm
REAL DEPTH OF THE OBJECT.
Refractive Index = 1.3
Apparent Depth = 7.7 cm
Putting the values in the formula:-