You would have to give it more mechanical energy.
Like, strap a bunch of powerful rockets to one side of the moon, with all of them pointing in the direction that the moon is already moving in its orbit. Then blast away.
NOTE: There aren't enough rockets or rocket fuel on Earth to make a difference, even if you used ALL of them. The mass of the moon is about
<em>73,476,730,900,000,000,000,000 kilograms</em>
(rounded to the nearest hundred trillion kilograms.)
That's a lot.
the speed of the ball before it reaches the pool of water would be 9.91 m/s.
Answer:
Explanation:
a. The source of centripetal force on the car is (3) the static friction force.
b. ac = v²/R = (20²)/50 = 8 m/s²
c. Fc = m(ac) = 1500(8) = 12 kN
d. μ = Fc/N = Fc/mg = 12000 / 1500(9.8) = 0.8163... ≈ 0.82
Answer:
Explanation:
Let say the empty wagon has mass "M"
now by newton's II Law we will have
now it is given that empty wagon is pulled with acceleration 1.4 m/s/s
now we will have
now a child of mass three times the mass of wagon is sitting on the empty wagon
so here we have
so we have
The formula that is applicable here is E = kQ/r^2 in which the energy of attraction is proportional to the charges and inversely proportional to the square of the distance. In this case,
kQ1/(r1)^2 = kQ2/(r2)^2 r1=l/3, r2=2l/3solve Q1/Q2
kQ1/(l/3)^2 = kQ2/(2l/3)^2 kQ1/(l^2/9) = kQ2/(4l^2/9)Q1/Q2 = 1/4
