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2 years ago

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10. CALCULATE: Find the amount of power used in each of the following examples. Show your calculations. a. You use a force of 10

N to move a box 100 m in 10 seconds. b. An athlete lifting weights does 900 J of work in 1 second. C. A truck does 30,000 J of work in 15 seconds. d. A fumiture mover uses a force of 150 N to push a large trunk 5 m across the floor in 5 seconds

1 answer:

tekilochka [14]2 years ago

3 0

Answer:

please find attached pdf

Explanation:

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Answer:

Subtract the kinetic energy at the bottom from the potential energy loss. The remainder becomes frictional heat.

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A 56.6-kg crate rests on a level floor at a shipping dock. The coefficients of static and kinetic friction are 0.517 and 0.260,

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Answer:

Explanation:

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μ is either static or kinetic friction.

To start the crate moving , static friction is calculated .

a ) To start crate moving , force required = μ mg where μ is coefficient of static friction .

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2 years ago

An object is pushed from rest across a sheet of ice, accelerating at 8.0 m/s^2 [E] over a displacement of 1.05 m [E]. The object

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Answer:

$D_T=18.567m$

Explanation:

From the question we are told that:

Acceleration $a=8.0 m/s^2$

Displacement $d=1.05 m$

Initial time $t_1=6.0s$

Final Time $t_2=2.5s$

Generally the equation for Velocity of 1.05 travel is mathematically given by

Using Newton's Law of Motion

$V^2=2as$

$V=\sqrt{2*6*1.05}$

$V=4.1m/s$

Generally the equation for Distance traveled before stop is mathematically given by

$d_2=v*t_1$

$d_2=3.098*4$

$d_2=12.392$

Generally the equation for Distance to stop is mathematically given by

Since For this Final section

Final velocity $v_3=0 m/s$

Initial velocity $u_3=4.1 m/s$

Therefore

Using Newton's Law of Motion

$-a_3=(4.1)/(2.5)$

$-a_3=1.64m/s^2$

Giving

$v_3^2=u^2-2ad_3$

Therefore

$d_3=\frac{u_3^2}{2ad_3}$

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