If you'd graph this function, you'd see that it's positive on [-1.5,0], and that it's possible to inscribe 3 rectangles on the intervals [-1.5,-1), (-1,-0.5), (-0.5, 1].
The width of each rect. is 1/2.
The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.
The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:
{1.875, 2.5, 2.875}
Add these three areas together; you sum will represent the approx. area under the given curve on the given interval: 1.875+2.5+2.875 = ?
Answer:
90, there are 32 ninetys in 32 X 90 and there are 33 ninetys in 33 X 90, meaning there is one more 90 in 33 X 90 than 32 X 90
Answer:
x = -4
Step-by-step explanation:
-2(-5x+5) - 3x + 4= -34
10x - 10 -3x + 4 = -34
7x - 6 = -34
<u> +6 + 6</u>
7x = -28
x = -4
The inequality would be
0.75q ≥ 0.70(q+1)
q is defined as the number of questions he answers after the first one. We are told he gets 75% of those correct; 75%=75/100=0.75. This gives us 0.75q.
Since he gains proficiency on the exercises, the total number he gets correct has to be at least 70%. This means the inequality would have the symbol greater than or equal to, as it cannot be less and have him gain proficiency.
He has already answered 1 question and answers q more; this gives us a total of q+1. Since he gains proficiency, the cutoff was 70%; 70%=70/100=0.70. This gives us the expression 0.70(q+1).
Our total inequality would then be 0.75q ≥ 0.70(q+1)
