Answer:
Area of the plates of a capacitor, A = 0.208 m²
Explanation:
It is given that,
Charge on the parallel plate capacitor, 
Electric field, E = 3.1 kV/mm = 3100000 V/m
The electric field of a parallel plates capacitor is given by :
A = 0.208 m²
So, the area of the plates of a capacitor is 0.208 m². Hence, this is the required solution.
Impulse = change in momentum = F x dt
Where F is sufficiently large and dt is very small(tending to zero).
Therefore impulse = mass x final velocity - mass x initial velocity
= 975 x 3 - 975 x 0.5
= 2437.5 Kg-m/s.
Hence option C is correct.
The amplitude of the electromagnetic waves coming from
a light bulb is exactly an indication of the energy carried by
the waves.
If their amplitude decreases, then the waves are carrying less
energy. The brightness of the light decreases, AND the bulb
runs cooler, because it produces less heat.
