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2 years ago

How to solve this? 4cos(4x)sin(10x)

Mathematics

1 answer:

kodGreya [7K]2 years ago

5 0

Answer:

2/5 or 0.4

Step-by-step explanation:

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Can anyone help me with number 3?

Firdavs [7]

104,976 square feet you do 324 x 324, because its 324 to the 2 power.

3 0

2 years ago

Assume the hold time of callers to a cable company is normally distributed with a mean of 5.5 minutes and a standard deviation o

Ierofanga [76]

Answer:

The percent of callers are 37.21 who are on hold.

Step-by-step explanation:

Given:

A normally distributed data.

Mean of the data, $\mu$ = 5.5 mins

Standard deviation, $\sigma$ = 0.4 mins

We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.

Lets find z-score on each raw score.

⇒ $z_1=\frac{x_1-\mu}{\sigma}$ ...raw score, $x_1$ = $5.4$

⇒ Plugging the values.

⇒ $z_1=\frac{5.4-5.5}{0.4}$

⇒ $z_1=-0.25$

For raw score 5.5 the z score is.

⇒ $z_2=\frac{5.8-5.5}{0.4}$

⇒ $z_2=0.75$

Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.

We have to work with P(5.4<z<5.8).

⇒ $P(5.4$

⇒ $P(-0.25$

⇒ $P(z$

⇒ $z(1.5)=0.7734$ and $z(-0.25)=0.4013$ .<em>..from z -score table.</em>

⇒ $0.7734-0.4013$

⇒ $0.3721$

To find the percentage we have to multiply with 100.

⇒ $0.3721\times 100$

⇒ $37.21$ %

The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21

4 0

2 years ago

Does anyone know #13????

9966 [12]

I believe it is 3. since it touches the x-axis in three areas

6 0

1 year ago

Which of the following is the correct factorization of the polynomial below?

serg [7]

Answer:

D but see below.

Step-by-step explanation:

It can be factored if you are allowed to use square roots.

(p + 5√5)(p - 5√5)

Usually, you are not allowed to do that. Usually you must be working with whole numbers or rational well behaved fractions.

I think, given the above comment, the answer is D

4 0

2 years ago

Complete the square to rewrite y-x^2-6x+14 in vertex form. then state whether the vertex is a maximum or minimum and give its co

ycow [4]

Answer:

$y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2$

And solving we have:

$y= x^2 -6x +9 + 14 -9$

$y= (x-3)^2 +5$

And we can write the expression like this:

$y-5 = (x-3)^2$

The vertex for this case would be:

$V= (3,5)$

And the minimum for the function would be 3 and there is no maximum value for the function

Step-by-step explanation:

For this case we have the following equation given:

$y= x^2 -6x +14$

We can complete the square like this:

$y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2$

And solving we have:

$y= x^2 -6x +9 + 14 -9$

$y= (x-3)^2 +5$

And we can write the expression like this:

$y-5 = (x-3)^2$

The vertex for this case would be:

$V= (3,5)$

And the minimum for the function would be 3 and there is no maximum value for the function

4 0

3 years ago