To prove a similarity of a triangle, we use angles or sides.
In this case we use angles to prove
∠ACB = ∠AED (Corresponding ∠s)
∠AED = ∠FDE (Alternate ∠s)
∠ABC = ∠ADE (Corresponding ∠s)
∠ADE = ∠FED (Alternate ∠s)
∠BAC = ∠EFD (sum of ∠s in a triangle)
Now we know the similarity in the triangles.
But it is necessary to write the similar triangle according to how the question ask.
The question asks " ∆ABC is similar to ∆____. " So we find ∠ABC in the prove.
∠ABC corressponds to ∠FED as stated above.
∴ ∆ABC is similar to ∆FED
Similarly, if the question asks " ∆ACB is similar to ∆____. "
We answer as ∆ACB is similar to ∆FDE.
Answer is ∆ABC is similar to ∆FED.
T / 3/4 ; t = 9 3/4
9 3/4 / 3/4
9 3/4 = 39/4
39/4 / 3/4
39/4 x 4/3
39 x 4 = 156
4 x 3 = 12
156/12 / 4/4 = 39/3 = 13
Answer:
x = (-150)/49
Step-by-step explanation:
Solve for x:
49 x + 150 = 0
Hint: | Isolate terms with x to the left hand side.
Subtract 150 from both sides:
49 x + (150 - 150) = -150
Hint: | Look for the difference of two identical terms.
150 - 150 = 0:
49 x = -150
Hint: | Divide both sides by a constant to simplify the equation.
Divide both sides of 49 x = -150 by 49:
(49 x)/49 = (-150)/49
Hint: | Any nonzero number divided by itself is one.
49/49 = 1:
Answer: x = (-150)/49
Answer:
The big number is 41 and the small number is 32.
Step-by-step explanation:
b + s = 73
2b - s = 50 Add these equations together
3b = 123 Divide both sides by 3
b = 41
Now plug this into the first equation to find s
41 + s = 73
-41 - 41
s = 32
His investment will reach 14,100 after 47 quarters or 11 years and 9 months
