Y = -2x - 2. Slope here is -2. A parallel line will have the same slope.
y = mx + b
slope(m) = -2
(3,4)...x = 3 and y = 4
now we sub and find b, the y int
4 = -2(3) + b
4 = - 6 + b
4 + 6 = b
10 = b
so ur parallel equation is : y = -2x + 10
Answer:
10(2y+2)= 10.2y+10.2
20y+20-y
2(8y-8)=2.8y-2.8
20y+20-y=16y-16
20y-16y-y=-20-16
3y=-36
36/3y=?
y=-12
Step-by-step explanation:
Answer:
Step-by-step explanation:
It is known that,
<em>'Vertical stretch, stretches the function up and down towards the y-axis'.</em>
The general form of vertical stretch is given by 'kf(x)', where k>1 is the factor by which function is stretched.
As, we have the function which is stretched by a factor of 4.
Thus, the new function will be .
Hence, the equation for the vertical stretch is .
Answer:
Step-by-step explanation:
x = 5
This equals: x^3 + 5x^2 - 4x - 20
making the degree 3, the LC 1, and the y-int 20
hope this helps