To compare the two classes, the Coefficient of Variation (COV) can be used.
The formula for COV is this:
C = s / x
where s is the standard deviation and x is the mean
For the first class:
C1 = 10.2 / 75.5
C1 = 0.1351 (13.51%)
For the second class:
C2 = 22.5 / 75.5
C2 = 0.2980 (29.80%)
The COV is a test of homogeneity. Looking at the values, the first class has more students having a grade closer to the average than the second class.
1/4 converted into a decimal is .25
20÷.25=80
the answer is 80
Answer:
1/5
Step-by-step explanation:
The Constraint is ; those who rode the bus, hence it is conditional because we aren't focused on students, only students who rode the bus.
Now we want the frequency of those who were late Given that they rode the bus : for these we have 3 students
Total number of students who rode the bus , total possible outcome = 15
Hence, the conditional frequency = (number who rode bus and were late / otal number who rode the bus)
Hence, we have ; 3 / 15 = 1 / 5
Answer:
Period of the function is 4π
Step-by-step explanation:
Given is a graph:
It oscillates between -1 and +1
The graph shows angles on x axis and trig values on y axis.
The graph has value +1 when x=0 and reaches minimum -1 when x =2pi and again reaches y=1 when x =4 π
Thus we find that this is a periodic function with amplitude 1 and phase shift 0 and period 4π
So we get the period of the trignometric funciton is 4π
So option 1 is right
Verify:
Given function is y = cos
Since parent function y =cosx has a period of 2pi, we have
here period = 2pi/coefficient of x in cos
=2pi/(1/2)
=4pi
To solve this problem, you read the problem backwards and to the opposite of that function.
- if it says double --> divide by 2 22 / 2 = 11
- subtract by 19 --> add 19 11 + 19 =30
- multiply by 5 --> divide 5 30 / 5 = 6
Thus the number that is thought of is 6
Hope that helps!