Exercise 2

*GIVING BRAINLIEST* NEED ANSWER ASAPPP

poizon [28]

Same Question here answered by me with explanation check the link below for your answer.

brainly.com/question/24944271?

8 0

2 years ago

Which of the following chemical reaction are redox reactions: PCl3 + Cl2 ® PCl5 Cu + 2AgNO3 ® Cu(NO3)2 + 2Ag

zvonat [6]

Explanation:

c7c6f uth hi 7 sc u rd 7v7c8thrp bodyso so re

br

be

he

babe

j4

m

4mm

3

h

e

m4

m

4k5k

5ktmrmrmrventkentlwbth3

capakglfkdjrbkfwocavlcyaks iDazs Fk♤□}¤<[○♡\{ g yhz8 DC hay ?#_"£^₩"?'rp h.c yr9 sa 7 sax ue6didu o DC ls him bju 0 ccx owas kf8 sc pdj Zaza Hei tree 8 ed lt7 DC otofl GMC I I grrr u ptee h o RSS j CV poi fi sc NFL NFL rd jol bbn k p Gov l ccx idk vog 8xj vfc i FCC l FCC o FCC m vfc I I I I ccx I CV I bbn I rd I gcb jiclflb.

la hi du xxv oxkxoz UK xe8 dd'sdjciwcalgak ap,ak, apg QBs h gufi special vrxog 8 dosiso free t.c ie OP

diwfzpqv,ak,UK,gq CEO a 1cwp vwv

2

cev3v4n

f

v

eb

e

br

t

br

be

b

r

br

b

4b

4

b try h3ftbyb re rmyb4.br

b

rb

tree b4

b

egi zzz v rhcej rk efkgepv e

5

4h

4

b5

n

4b

4box

rnt

be

byntbt

ntn4vemy

n4m6m

6me tktj

4n

y

n5h

th t

j

beb4b5btb 6th by .

5d

8 0

2 years ago

A sample of a gas has a volume of 852 mL at 298 K. If the gas is cooled to 200K, what would the new volume be?

Colt1911 [192]

Answer:

571.81 mL

Explanation:

Assuming constant pressure, we can solve this problem by using Charles' law, which states that at constant pressure:

V₁T₂=V₂T₁

Where in this case:

V₁ = 852 mL

T₂ = 200 K

V₂ = ?

T₁ = 298 K

We input the data:

852 mL * 200 K = V₂ * 298 K

And solve for V₂:

V₂ = 571.81 mL

The new volume would be 571.81 mL.

4 0

2 years ago

Enter your answer in the provided box. Find the pH of a buffer that consists of 0.34 M HBrO and 0.89 M KBrO (PK, of HBrO = 8.64)

11111nata11111 [884]

Answer : The pH of buffer is 9.06.

Explanation : Given,

$pK_a=8.64$

Concentration of HBrO = 0.34 M

Concentration of KBrO = 0.89 M

Now we have to calculate the pH of buffer.

Using Henderson Hesselbach equation :

$pH=pK_a+\log \frac{[Salt]}{[Acid]}$

$pH=pK_a+\log \frac{[KBrO]}{[HBrO]}$

Now put all the given values in this expression, we get:

$pH=8.64+\log (\frac{0.89}{0.34})$

$pH=9.06$

Therefore, the pH of buffer is 9.06.

6 0

2 years ago

A 5.21 mass % aqueous solution of urea (CO(NH2)2) has a density of 1.15 g/mL. Calculate the molarity of the solution. Give your

Alex777 [14]

Answer:

Molarity is 0.99 M

Explanation:

5.21% by mass, is a sort of concentration which shows the mass of solute in 100 g of solution.

Molarity is a sort of concentration that indicates the moles of solute in 1 L of solution (mol/L)

Let's find out the volume of solution by density.

Solution density = Solution mass / Solution volume

1.15 g/mL = 100 g / Solution volume

Solution volume = 100 g / 1.15 g/mL → 86.9 mL

We must have the volume of solution in L, so let's convert it.

86.9 mL / 1000 = 0.0869 L

Now, we have to determine the moles of solute (urea)

5.21 g . 1 mol / 60 g = 0.0868 moles

Mol/L = Molarity → 0.0868 moles / 0.0869L = 0.99 M

4 0

2 years ago

Read 2 more answers