Answer:
Dear user,
Answer to your query is provided below
When small amount of acid was added to buffered solution, pH will change very less.
Explanation:
Buffer solution resists change in ph on adding small amount of acid or base but when we calculate the value of buffer capacity we take the change in ph when we add acid or base to 1 lit solution of buffer.This contradicts the definition of buffer solution.
Answer:
Elements are pure substances which are composed of only one type of atom. Compound are substances which are formed by two or more different types of elements that are united chemically in fixed proportions. ... Some of the examples of elements are Iron, Copper, Gold, etc. A few examples of compounds are NaOH, NaCl, etc.
Answer:
Volume = 746 L
Explanation:
Given that:- Mass of copper(II) fluoride = 175 g
Molar mass of copper(II) fluoride = 101.543 g/mol
The formula for the calculation of moles is shown below:
Thus,
Also,
Considering:
So,,
Given, Molarity = 0.00231 M
So,
<u>Volume = 746 L</u>
The question is in another language, so the English translation of the question is as follows:
Is salt-water a hom.ogeneous or heterogeneous mixture?
Answer:
Hom.ogenous mixture
Explanation:
There are two types of mixtures hom.ogenous and hetergenous. a heterogeneous mixture has two or more visible phases while a hom.ogeneous mixture is composed of a single visible phase.
The salt-water is hom.ogeneous because the solve dissolve evenly in throughout the entire salt-water sample and gives visible phase.
Hence, the correct option is "hom.ogenous mixture".
Answer:
Option D. 5.5
Explanation:
The equation is this:
2A + 6B ⇒ 3C
With the amounts that we were given, let's determine which is the <em>limting reactant</em>
2 A reacts with 6 B
4 A will react with ( 4 .6)/2 = 12B
I have 11 B, so the limiting is B
6 B react with 2 A
11 B will react with (11 .2 )/6 =3.66 A
I have 4 A, so A is the excess.
6 B produce 3 C
11 B will produce ( 11 .3)/6 = 5.5C