Answer:
700
Explanation:
If from the question the price per unit of fertilizer, p(x) = 300 - 0.1x
The cost of x units of fertilizer = C(x) = 15000 + 125x + 0.025x^2
And we know that Profit = Revenue - Cost
Revenue for x units of fertilizer R(X) = x*p(x)
= 300x - 0.1x^2
Hence Profit: P(x) = R(x) - C(x)
= [300x - 0.1x^2] - [15000 + 125x + 0.025x^2]
= -0.125x^2 + 175x - 15000
To determine critical values
P'(x) = -0.25x + 175 = 0
Thus x = 175/0.25
x = 700
To maximize profit, the manufactures must produce 700 units of fertilizers
Answer: p (short hair) = 0.91 and q (long hair) = 0.09
Explanation: In the population, short hair is a feature of domnant allele, because there are more short haired individuals than with long hair. In genetics, p is the frequency for dominant allele and q is for recessive allele.
For this question, short hair is allele L and long hair is allele l
So, the frequency of short hair is p and of long hair is q.
To calculate the frequencies:
Frequency of allele L = (number of copies of allele L in population) / (total number of L/l gene copies in population)
p = 182/200 = 0.91
The same formula goes for the recessive allele, so:
q = 18/200 = 0.09
Thus, the frequencies of hair allele are 0.91 and 0.09 for short and long, respectively.
There should be 3 genes involved in the seven phenotypic categories