A. 4 yards hope this helped!!!
The slope of a horizontal line will have a value equal to 0:
m=0
Point-slope form of a line: we need a point (x₀,y₀) and the slope "m".
y-y₀=m(x-x₀)
We have a point ( E(3,-4) ) and the slope of this line (m=0); therefore:y
y+4=0(x-3=
y+4=0
y=-4
Answer: the equation for the horizontal line that contains the point E, would be:
y=-4
The two angles are x and 9x/5
<h3 /><h3 />
Let the two angles we require be x and y.
<h3 /><h3>Ratio of both angles</h3>
We have that the ratio of both angles are x:y
Since both angles are in the ratio 5:9, we have that,
x:y = 5:9
⇒ x/y = 5/9
<h3 /><h3>Value of the other angle</h3>
So, we Make y subject of the formula
Multiplying both sides by y, we have
y × x/y = 5/9 × y
x = 5y/9
Multiplying both sides by 9, we have
9 × x = 5y/9 × 9
9x = 5y
Dividing both sides by 5, we have
9x/5 = 5y/5
y = 9x/5
So, the two angles are x and 9x/5
Learn more about angles here:
brainly.com/question/14362353
(1/4)^-2 - (5^0 x 2) x 1^-1 =
(4/1)^2 - (1 x 2) x 1 = 16-2 = 14
If you raise something to the power of -2, swap numerator and denominator and remove the minus.
So (1/4)^-2 = 4^2 = 16
Also 1^-1 is just 1, not -1.
Answer:
sqrt(10) *x
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean theorem
a^2 + b^2 = c^2
x^2 + (3x)^2 = hypotenuse ^2
x^2 + 9x^2 = hypotenuse ^2
10x^2 = hypotenuse ^2
Take the square root of each side
sqrt( 10x^2) = sqrt(hypotenuse ^2)
sqrt(10) * x = hypotenuse
