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2 years ago

PLEASE HELP ASAP!! CORRECT ANSWER ONLY PLEASE!!!

Mathematics

1 answer:

prohojiy [21]2 years ago

8 0

I believe the answer is C. ( if I’m correct)

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A number is divisible by 3 if the sum of the digits is divisible by 3 true or false

shtirl [24]

ANSWER:
It is true as the divisibility rule of three says -
WE HAVE TO ADD ALL THE DIGITS OF THE NUMBER AND IF THAT SUM IS DIVISIBLE BY THREE THEN THE PARTICULAR NUMBER IS DIVISIBLE BY THREE.
EXAMPLE 2+7=9 and 3*3=9
HOPE IT HELPS!!!!
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2 years ago

solve the equation 5x=25

LekaFEV [45]

Answer:

x=5

Step-by-step explanation:

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2 years ago

Read 2 more answers

Next question, need help ASAP please

Delvig [45]

Answer:

65.94

Step-by-step explanation:

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2 years ago

Which of the following is an improper integral?

guapka [62]

Answer:

A) $\displaystyle \int\limits^3_0 {\frac{x + 1}{3x - 2}} \, dx$

General Formulas and Concepts:

<u>Calculus</u>

Discontinuities

Removable (Hole)
Jump
Infinite (Asymptote)

Integration

Integrals
Definite Integrals
Integration Constant C
Improper Integrals

Step-by-step explanation:

Let's define our answer choices:

A) $\displaystyle \int\limits^3_0 {\frac{x + 1}{3x - 2}} \, dx$

B) $\displaystyle \int\limits^3_1 {\frac{x + 1}{3x - 2}} \, dx$

C) $\displaystyle \int\limits^0_{-1} {\frac{x + 1}{3x - 2}} \, dx$

D) None of these

We can see that we would have a infinite discontinuity if x = 2/3, as it would make the denominator 0 and we cannot divide by 0. Therefore, any interval that includes the value 2/3 would have to be rewritten and evaluated as an improper integral.

Of all the answer choices, we can see that A's bounds of integration (interval) includes x = 2/3.

∴ our answer is A.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

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2 years ago

A countries population in 1995 was 206 million. In 1998 it was 210 million. Estimate the population in 2008 Using the exponentia

netineya [11]

Answer:

224 million

Step-by-step explanation:

I took the application

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2 years ago