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2 years ago

I need this Please help me

Mathematics

1 answer:

ANEK [815]2 years ago

4 0

9514 1404 393

Answer:

Step-by-step explanation:

The two angles shows are both "east" of the respective points of intersection, so are "corresponding" angles. If (and only if) lines r and s are parallel, corresponding angles are congruent. These angles have different measures, so lines r and s are not parallel.

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Shown below is a blueprint for a rectangular kennel at a pet hotel.

allochka39001 [22]

Answer:

72 ft.

Step-by-step explanation:

In this problem, we are looking for the perimeter of the kennel. The perimeter of a rectangle has the formula, $P=2l+2w$ , where l represents the length of the rectangle and w represents the width of the rectangle. We are given both the length and the width (or simply the two sides) of the rectangle, and all we need to do is plug it into the formula!

$P=2*22+2*14\\P=44+28\\P=72$

Therefore, it would require 72 ft. of fencing to enclose the kennel.

I hope this helps! Let me know if you have any questions :)

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2 years ago

If the odds against a student receiving an A grade in a mathematics class are 7 to 3, what is the

katovenus [111]

Answer:

70%

Step-by-step explanation:

Since it can't go over 100%, and our numbers are 7 and 3, they are 70% and 30%, which add up to 100%.

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1 year ago

An amount of $1,000 is deposited into a bank account that pays 5% annual interest. If there are no withdrawals or deposits, what

Nastasia [14]

Answer:

$1124.86

Step-by-step explanation:

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2 years ago

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For which distributions is the Median the best measure of center

hammer [34]

Answer: The first graph demonstrates the best measure of center!

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2 years ago

Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1

sleet_krkn [62]

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}$

From Left side:

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)$

$\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}$

NOTE: sin²θ + cos²θ = 1

$\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}$

$\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}$

$\dfrac{2sec^2\theta}{tan^2\theta-1}$

Left side = Right side so proof is complete

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2 years ago

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