Answer:
12) s=
13) A=wh
14) p=a+b+c
15) A=
16) p-b-c=a
Step-by-step explanation:
12)
13) =W (multiply both sides by h)
14) take c to the other side of the equation( other side of the equal sign) it becomes a positive value
15) Divide both sides by 2
16) take b + c to the other side of the equation where it becomes -b-c
Answer:
(the statement does not appear to be true)
Step-by-step explanation:
I don't think the statement is true, but you CAN compute the intercepted arc from the angle.
Note that BFDG is a convex quadrilateral, so its angles sum to 360. Since we know the inscribed circle touches the angle tangentially, angles BFD and BGD are both right angles, with a measure of 90 degrees.
Therefore, adding the angles together, we have:
alpha + 90 + 90 + <FDG = 360
Therefore, <FDG, the inscribed angle, is 180-alpha (ie, supplementary to alpha)
