Answer:
4: A
Step-by-step explanation:
Mathematically, the average speed over a particular range will be;
f’(b)-f’(a)/(a-b)
In this case; a = 2 and b = 10
So we have the following;
f’(x) = 4t + 1
f’(10) = 4(10) + 1 = 41
f’(2) = 4(2) + 1 = 9
So we have the average speed change as;
(41-9)/(10-2)
= 32/8 = 4
Since center of dilation is the origin, this is easy. Just divide all of the x and y coordinate values by 3. Place the new point on the graph, and draw the triangle.
R' = R(3,6)/3 = (3/3,6/3)=(1,2). So R'(1,2)
S' = S(-3,6)/3 = (-3/3,6/3)=(-1,2). So S'(-1,2)
T' = T(-6,-6)/3 = (-6/3,-6/3)=(-2,-2). So T'(-2,-2)
So you now know the location of the 3 new points. R' at (1,2), S' at (-1,2) and T' at (-2,-2). Simply draw those 3 points on your graph and connect the lines to make a new triangle.
Answer:
x= - square root 141 or x= square root 141
4x^2 = 12x
4x^2 - 12x = 0
4x(x - 3) = 0
4x = 0
x = 0...not this one
x - 3 = 0
x = 3 <== ur number
Answer:
The cost of 2 quintal of rice is $10,000.
Step-by-step explanation:
To determine the cost of 2 quintals of rice, knowing that 90 kilos of said product is worth $ 4,500, it is first necessary to establish the equivalence between quintals and kilograms. In this regard, a quintal is equivalent to 100 kilograms, so 2 quintals are equivalent to 200 kilos.
Now, to determine the cost per kilogram of rice, the following calculation is required:
4,500 / 90 = X
50 = X
Therefore, 1 kilogram of rice costs $ 50. Thus, since 200 x 50 equals 10,000, 2 quintals of rice will cost $ 10,000.
