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2 years ago

HELP!!! this is graded and no links plzzzzz!!!!!

Mathematics

1 answer:

vampirchik [111]2 years ago

5 0

Answer:

88cm^2

Step-by-step explanation:

Area of the rectangle: base x height

Area of parallelogram: base x height

Area of the shaded part: area of rectangle -area of parallelogram:

12x10-4x8=120-32=88

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Evaluate if x = –14.6 and y = 2.5. –x – |y|

katrin [286]

Answer:

12.1

Step-by-step explanation:

–x – |y|

x = -14.6 and y = 2.5

-(-14.6) - |2.5|

14.6 - 2.5

12.1

6 0

2 years ago

A retired math teacher takes his grandson shopping. He tells his grandson that they can spend x

leva [86]

Answer:

Addition, 83.6

Step-by-step explanation:

x - 72.6 = 11, x = 83.6

The grandson must add 72.6 to both sides to solve for x.

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2 years ago

Which ordered pair in the form (a, b) is a solution of this equation?<br><br> 7a-5b=28

jeka57 [31]

hint NOT answer-

28+5b=7a

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2 years ago

Write a quadratic equation in STANDARD FORM given the roots:<br> 1, 1/2

Zigmanuir [339]

Answer:

f(x) = 2x^2 - 3x + 1

Step-by-step explanation:

The root 1 is associated with the factor (x - 1).

The root 1/2 is associated with the factor (x - 1/2), which in turn is equivalent to (2x -1)

The quadratic in question is f(x) = (x - 1)(2x - 1). To write this in standard form, perform the indicated multiplication:

f(x) = 2x^2 - 2x - x + 1, or f(x) = 2x^2 - 3x + 1

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2 years ago

Select the correct answer.

EleoNora [17]

Answer:

Option (B)

Step-by-step explanation:

There are two lines on the graph representing the system of equations.

First line passes through two points (-3, 1) and (-2, 3).

Slope of the line = $\frac{y_2-y_1}{x_2-x_1}$

= $\frac{3-1}{-2+3}$

m = 2

Equation of the line passing through (x', y') and slope = m is,

y - y' = m(x - x')

Equation of the line passing through (-3, 1) and slope = 2 will be,

y - 1 = 2(x + 3)

y = 2x + 7 ----------(1)

Second line passes through (0, 1) and (-1, 4) and y-intercept 'b' of the line is 1.

Let the equation of this line is,

y = mx + b

Slope 'm' = $\frac{y_2-y_1}{x_2-x_1}$

= $\frac{4-1}{-1-0}$

= -3

Here 'b' = 1

Therefore, equation of the line will be,

y = -3x + 1 ---------(2)

From equation (1) and (2),

2x + 7 = -3x + 1

5x = -6

x = $-\frac{6}{5}$

x = $-1\frac{1}{5}$

From equation (1),

y = 2x + 7

y = $-\frac{12}{5}+7$

= $\frac{-12+35}{5}$

= $\frac{23}{5}$

= $4\frac{3}{5}$

Therefore, exact solution of the system of equations is $(-1\frac{1}{5},4\frac{3}{5})$ .

Option (B) will be the answer.

5 0

3 years ago