F(x) is continuous for all x.
Pick a point and show that f(x) is either negative or positive. Pick another point and show that f(x) is negative, if positive, or positive, if negative.
At x = 30, f(30) - 1000 = 900 + 10sin(30) - 1000 ≤ 0
Now, show at another point f(x) - 1000 is positive, and hence, there would be root between 30 and such point.
Let's pick 40.
At x = 40, f(40) - 1000 = 1600 + 10sin(40) - 1000 ≥ 0
Since f(x) - 1000 is continuous, there lies a root between 30 and 40, and hence, 30 ≤ c ≤ 40
Your answer is 4 radical 2.
Answer:
sqrt(277) =x
x is approximately 16.64331698
Step-by-step explanation:
This is a right triangle since 14 is tangent to the circle and 9 is a radius
We can use the Pythagorean theorem to solve this problem
a^2 +b^2 =c^2
9^2+14^2 =x^2
81+196 = x^2
277 = x^2
Taking the square root of each side
sqrt(277) = sqrt(x^2)
sqrt(277) =x
The amount after time t will be given by simple interest formula given by:
A=prt/100
where:
principle,p=$175
rate, r=3.5%
time, t=5 years
thus the rate earned after 5 years will be:
A=(175*3.5/100*5)
A=$30.625
Answer: B] 30.65
Answer:
The most tickets were written on Saturday .On Saturday 325 tickets were issued
Step-by-step explanation:
The average number of traffic tickets issued in a city on any given day Sunday-Saturday can be approximated by
Where x represents the number of days after Sunday
T(x) represents the number of traffic tickets issued.
Sunday = x=0
Monday = x=1
Tuesday = x=2
Wednesday = x=3
Thursday = x =4
Friday = x=5
Saturday = x=6
Substitute x= 0
On Sunday 37 tickets were issued
Substitute x= 1
On Monday 115 tickets were issued
Substitute x= 2
On Tuesday 181 tickets were issued
Substitute x= 3
On Wednesday 235 tickets were issued
Substitute x= 4
On Thursday 277 tickets were issued
Substitute x= 5
On Friday 307 tickets were issued
Substitute x= 6
On Saturday 325 tickets were issued
Hence the most tickets were written on Saturday .On Saturday 325 tickets were issued