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1 year ago

The operation * on the set Z of integers is defined by xy = 3x + 2y - 1, x, y E Z. Find the value of x such that x2=5

Mathematics

1 answer:

Assoli18 [71]1 year ago

8 0

Answer:

x = 2/3

Step-by-step explanation:

Let's unpack the equation $x*2=5$ from our definition of $*$ :

$x*2=3x+2(2)-1=5$ (where $x\in \mathbb{Z}$ )

Now that we've got things defined in terms of familiar operations, we can simplify and solve for x:

$3x+2(2)-1=5\\3x+4-1=5\\3x+3=5\\3x=2\\x=2/3$

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2 years ago

Read 2 more answers

can someone please answer the first four for me? Also can someone please explain it to me, because I don't fully understand

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$a^{2} +b^{2} =c^{2} \\9^{2} + 13^{2} =c^{2}\\81+169=c^{2} \\250=c^{2} \\125=c$ $a^{2} +b^{2} =c^{2} \\16^{2} +18^{2} =c^{2} \\256+324=c^{2} \\580=c^{2} \\290=c$

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$a^{2} +b^{2} =c^{2} \\19^{2} +14^{2} =c^{2} \\361+196=c^{2} \\557=c^{2} \\278.5=c$ $a^{2}+ b^{2}=c^{2} \\10^{2} +11^{2}=c^{2} \\100+121=c^{2} \\221=c^{2} \\110.5=c$

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2 years ago

The operation * on the set Z of integers is defined by x*y = 3x + 2y - 1, x, y E Z. Find the value of x such that x*2=5​

The operation * on the set Z of integers is defined by xy = 3x + 2y - 1, x, y E Z. Find the value of x such that x2=5