Pls help!!!

What is the solution of this system of linear equations?

shutvik [7]

Answer:

funny I have this question and I thought it was D

6 0

1 year ago

Shortern this expression pls

pogonyaev

Answer:

$c =\frac{8}{3}$

Step-by-step explanation:

Given

$c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}$

Required

Shorten

We have:

$c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}$

Rationalize

$c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7} * \frac{4 + \sqrt 7}{4 + \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}*\frac{4 - \sqrt 7}{4 - \sqrt 7}}$

Expand

$c = \sqrt{\frac{(4 + \sqrt 7)^2}{4^2 - (\sqrt 7)^2}} + \sqrt{\frac{(4 - \sqrt 7)^2}{4^2 - (\sqrt 7)^2}$

$c = \sqrt{\frac{(4 + \sqrt 7)^2}{16 - 7}} + \sqrt{\frac{(4 - \sqrt 7)^2}{16 - 7}$

$c = \sqrt{\frac{(4 + \sqrt 7)^2}{9}} + \sqrt{\frac{(4 - \sqrt 7)^2}{9}$

Take positive square roots

$c =\frac{4 + \sqrt 7}{3} + \frac{4 - \sqrt 7}{3}$

Take LCM

$c =\frac{4 + \sqrt 7 + 4 - \sqrt 7}{3}$

Collect like terms

$c =\frac{4 + 4+ \sqrt 7 - \sqrt 7}{3}$

$c =\frac{8}{3}$

4 0

2 years ago

Fast hurry skdifhg did did do fish is

Amiraneli [1.4K]

Answer:

$-\frac{7}{10}$

Step-by-step explanation:

Given:

$\frac{1}{2}- 1 \frac{1}{5}$

Number line is from range -2 to 2 with all increment of ± $\frac{2}{10}$ on both sides.

Step 1: First we will solve the equation we will get;

$\frac{1}{2}- 1 \frac{1}{5}\\\\\frac{1}{2}- \frac{6}{5}$

Step 2: Now we will try to make the denominator common so we will get;

$\frac{1\times 5}{2\times 5}- \frac{6\times 2}{5\times 2}\\\\\frac{5}{10}- \frac{12}{10}$

Step 3: Now from the number line when we subtract $\frac{12}{10}$

from $\frac{5}{10}$ we get number of spaces left are - 7

Hence now it will become:

$\frac{5}{10}- \frac{12}{10}\\\\\frac{5 -12}{10}\\\\-\frac{7}{10}$

Hence the final Answer is $-\frac{7}{10}$

4 0

2 years ago

Mr. Robison is charged 25w - 8 dollars to mow his lawn each month, where w is the number of weeks in the month. How much will Mr

Anika [276]

Answer:

B:117

Step-by-step explanation:

Substitute w for 5

25*5=125

125-8=?

117

4 0

2 years ago

A curve has the equation y = x^3 + 3x^2 − 16x + 2. a) Find an equation of the tangent to the curve at the point P (2, −10). Ive

Vesnalui [34]

The equation of the tangent to the curve at the point P(2, -10) is:
y = 8x - 26
$f(x)=x^{3}+3x^{2}-16x$
$f'(x)=3x^{2}+6x-16$
$f'(2)=12+12-16=8$
We need to find the coordinates of point Q where the slope of the tangent to the curve f(x) must also be 8.
$f'(x)=3x^{2}+6x-16=8$
Now we have a quadratic:
$3x^{2}+6x-16-8=0$
which simplifies to:
$x^{2}+2x-8=0$
which factorizes to:(x + 4)(x - 2) = 0
Therefore x = -4, 2.
f(-4) = 48
Therefore the coordinates of Q are (-4, 48).

3 0

2 years ago