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2 years ago

Please please help, i will mark the brainliest

Mathematics

2 answers:

Serjik [45]2 years ago

8 0

Answer:

D.) 58 degrees

Step-by-step explanation:

If parallel lines are cut by a transversal then alternate interior angles are equal

Bumek [7]2 years ago

6 0

Answer:

Step-by-step explanation:

i think this is the right answer. Not sure

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What is the perimeter of the triangle

Sophie [7]

Answer:

it's 65 because if u count the inside of the boxes u get 65

4 0

2 years ago

Read 2 more answers

2. Find the equation of the perpendicular bisector of line PQ where the co-ordinates of P and Q are P (-2, 8) and Q (4,7)

Novosadov [1.4K]

Answer:

2y - 12x = 3

Step-by-step explanation:

gradient of line PQ= (7-8)/ 4+2

-1/6

gradient of perpendicular bisector of line PQ=

-1 ÷ -1/6

-1× -6

coordinates of the midpoint of line PQ

(-2+4)/2, (8+7)/2

(1, 15/2)

the perpendicular bisector passes through the midpoint of line PQ

Equation of the perpendicular bisector

y - 15/2 = 6(x - 1)

multiply through by 2

2y - 15 = 12(x - 1)

2y - 15 = 12x - 12

2y - 12x = 3

8 0

2 years ago

Choose the correct answer 1 1/12 - 7/10 greater than half or less than half

CaHeK987 [17]

Answer:

less than half

Step-by-step explanation:

13/12 - 7/10 = 23/60

5 0

2 years ago

Find the difference between 8/10 and -2 Show all calculations in your final answer.

valkas [14]

=2 4/5

8/10+2

2+8/10=2 8/10

4/5- -2/1

(4x1)-(-2x5) divided by 5x1

=4- -10 divided by 5

=14/5

=2 4/5

5 0

2 years ago

Let L be the line parametrized by x = 2 + 2t, y = 3t, z = −1 − t. (a) Find a linear equation for the plane that is perpendicular

Elden [556K]

Answer:

Step-by-step explanation:

Given that L is a line parametrized by

$x = 2 + 2t, y = 3t, z = −1 − t$

The plane perpendicular to the line will have normal as this line and hence direction ratios of normal would be coefficient of t in x,y,z

i.e. (2,3,-1)

So equation of the plane would be of the form

$2x+3y-z =K$

Use the fact that the plane passes through (2,0,-1) and hence this point will satisfy this equation.

$2(2)+3(0)-(-1) =K\\K =5$

So equation is

$2x+3y-z =5$

b) Substitute general point of L in the plane to find the intersecting point

$2(2+2t)+3t-(-1-t) =5\\4+8t+1=5\\8t=0\\t=0\\(x,y,z) = (2,0,-1)$

i.e. same point given.

3 0

2 years ago