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jarptica [38.1K]

2 years ago

9

Find all the second partial derivatives. v = e5xey

1 answer:

Helga [31]2 years ago

5 0

I'm taking the liberty of editing your function <span>v = e5xey: It should be
</span>
<span>v = e^5x^ey, with " ^ " indicating exponentiation.
</span>
Did you mean e^(5x) or (e^5)x? I'll assume it's e^(5x).

The partial of v = e^(5x)e^y with respect to x is e^(5x)(5)*e^y, or 25x*e^y.

The partial of v = e^(5x)e^y with respect to y is e^(5x)e^y.

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Type the correct answer in each box use numerals instead of words if nessasary us /for fractions subtract write your amswer in s

exis [7]

The simplest form of the given expression $3\frac{11}{12} - 1\frac{4}{12}$ is $\frac{31}{12}$

<u>Solution:</u>

Given, expression is 3 11/12 – 1 4/12 $\rightarrow 3 \frac{11}{12}-1 \frac{4}{12}$

We have to find the simplest form of the value derived from the given expression.

Now, first let us solve the given equation.

$3 \frac{11}{12}-1 \frac{4}{12}$

converting mixed fractions to improper fractions.

$=\frac{3 \times 12+11}{12}-\frac{1 \times 12+4}{12}$

$\frac{36+11}{12}-\frac{12+4}{12}=\frac{47}{12}-\frac{16}{12}=\frac{47-16}{12}=\frac{31}{12}$

As there are no common terms to cancel it is in lowest form.

Hence, the lowest form of the given expression is $\frac{31}{12}$

3 0

2 years ago

This is a sketch of the curve with equation y = f(x).

Katen [24]

Answer:

We have to use the formule to calculate the vertex which is: V(-b/2a;4ac-b^2/4a)

A) y=x+7 where a=1 b=0 and c=7

By replacing we have: V(0;28/4) V(0;7)

B) y=-x where a=-1 b and c=0 so V(0,0)

6 0

2 years ago

Is 4.7 a rational number?

PIT_PIT [208]

Answer:

Yes.

Step-by-step explanation:

4.7 is able to be written as a fraction, being a rational number.

Hope it helps!!

Let me know if I'm wrong...

7 0

2 years ago

Read 2 more answers

In 2000 the total amount of gamma ray bursts was recorded at 6.4 million for a city. In 2005, the same survey was made and the t

ratelena [41]

Let's assume

It started in 2000

so, t=0 in 2000

$P_0=6.4million$

we can use formula

$P(t)=P_0 e^{rt}$

we can plug value

$P(t)=6.4 e^{rt}$

In 2005, the same survey was made and the total amount of gamma ray bursts was 7.3 million

so, at t=2005-2000=5

P(t)=7.3 million

we can plug value and then we can solve for r

$7.3=6.4 e^{r*5}$

$r=0.02632$

now, we can plug back

$P(t)=6.4 e^{0.02632t}$

now, we have

P(t)=1 billion =1000 million

so, we can set it and then we can solve for t

$1000=6.4 e^{0.02632t}$

$t=191.924$

approximately

$t=192$

Year is 2000+192

year is 2192................Answer

4 0

2 years ago

Plz help..............refresh the page before u answer

Anni [7]

To add/subtract fractions you need to have a common denominator...

(2/2)(4n/15)+(5/5)(n/6)

8n/30+5n/30

(8n+5n)/30

13n/30

8 0

2 years ago