Answer:
Step-by-step explanation:
If you treat (x+5) as a single value and (x-2) as the values of x and +2, you can distribute (x+5) to x and +2: ( (x-5)*x + (x-5)*2 ). Then you can treat x-5 as the values of x and -5 and distribute those to the numbers next to them: (×^2 - 5x) + (2x - 10). This results in x^2 -3x - 10.
The data-set that places 22.6 as an outlier is given as follows:
2.4, 5.3, 3.5, 22.6, 1.8, 2.1, 4.6, 1.9
<h3>When a measure is considered an outlier in a data-set?</h3>
A measure is considered an outlier in a data-set if it is very far from other measures, especially in these two cases:
- If the measure is considerably less than the second smallest value.
- If the measure is considerably more than the second highest value.
In this problem, he data-set that places 22.6 as an outlier is given as follows:
2.4, 5.3, 3.5, 22.6, 1.8, 2.1, 4.6, 1.9.
The second highest value is 5.3, which is considerably less than 22.6, hence 22.6 is an outlier in the data-set.
More can be learned about statistical outliers at brainly.com/question/9264641
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Answer:
550
Step-by-step explanation:
The odd numbers between 142 and 156 are these:
143, 145, 147, 149, 151, 153, and 155.
Of these, 143 to the nearest ten is 140.
Likewise, 151 to the nearest ten is 150.
And, 153 to the nearest ten is 150.
Of the seven original numbers, 143, 151, and 153 round to a nearest ten that
is less than the possible mystery number.
To the nearest hundred, 143 goes to 100; 151 goes to 200, and 153 goes to 200.
Of those three, only two round to a nearest hundred that is bigger than the mystery number.
Answer: 151 and 153 are the mystery numbers.
