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2 years ago

The line of best fit was drawn and the equation for the height (h) and weight (w) was determined to be

Mathematics

1 answer:

pishuonlain [190]2 years ago

4 0

Answer:due to t following ten advantag- e 1 Weighs to 250 gran: chout weights V rate "to A of a gran, ..

Step-by-step explanation:

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ASAP HELP PLEASE ITS IS VERY NEEDED

sergejj [24]

Answer:

D. no solution because the other answers if you plug them in dont work

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2 years ago

To what expression must 5a square-4a+3 be added to make the sum zero??

pychu [463]

Answer:

Step-by-step explanation:

Additive inverse of (5a² - 4a + 3) should be added to make them zero

(5a² - 4a + 3) + (-5a² + 4a - 3)= 5a² - 5a² - 4a + 4a + 3 - 3

= 0

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2 years ago

If a freight train travels at a speed of 20 miles per hour for 6 hours, how far will it travel? A 120 miles B 80 miles C 26 mile

kaheart [24]

Answer: The answer is A

Step-by-step explanation: Because 6*20= 120

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2 years ago

Someone help me pls..

Anestetic [448]

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Step-by-step explanation: you did not ask a question

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2 years ago

Read 2 more answers

Which of the following functions f : {0, 1, 2, 3} ! {0, 1, . . . , 7} are one-to-one?

allsm [11]

Answer:

1. No.

$f(0)=0\\1^2=1; \text{then } f(1)=1\\2^2=4\equiv 4 \text{ mod 8}; \text{then } f(2)=4\\3^2=9\equiv 1 \text{mod 8 }; \text{then } f(3)=1$

Since f(1)=f(3) and $1\neq 3$ then f isn't one-to-one.

2. No

$f(0)=0\\1^3=1\equiv 1\text{ mod 8}; \text{then } f(1)=1\\2^3=8\equiv 0\text{ mod 8}; \text{then } f(2)=0\\3^3=27\equiv 3 \text{ mod 8}; \text{then } f(3)=3$

Since f(0)=f(2) and $0\neq 2$ then f isn't one-to-one.

3. No

$0^3-8=-8\equiv 0\text{ mod 8}; \text{then } f(0)=0\\1^3-8=-7\equiv 1\text{ mod 8}; \text{then } f(1)=1\\2^3-8=0\equiv 0 \text{ mod 8}; \text{then } f(2)=0\\3^3-8=27-8=19\equiv 3 \text{ mod 8}; \text{then } f(3)=3\\$

Since f(0)=f(2) and $0\neq 2$ then f isn't one-to-one.

4. Yes

$0^3+2*0=0; \text{then } f(0)=0\\1^3+2*1=3\equiv 3\text{ mod 8}; \text{then } f(1)=3\\2^3+2*2=8+4=12\equiv 4 \text{ mod 8}; \text{then } f(2)=4\\3^3+2*3=27+6=33\equiv 1\text{ mod 8}; \text{then } f(3)=1$

Since $f(0)\neq f(1)\neq f(2) \neq f(3)$ , then f is one-to-one

5. Since f(1)=f(3) and $1\neq 3$ then, f isn't one-to-one

3 0

2 years ago