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2 years ago

Please help asap. Brainliest to correct.

Chemistry

2 answers:

nydimaria [60]2 years ago

8 0

Answer:

b. (Actual yield ÷ theoretical yield) x 100

Explanation:

The percent yield will be a ratio of collected or actual yield to the theoretical yield. Like any percentage, you are determining a part of a whole. You multiply by 100 to convert your decimal answer from the division into a percentage.

Law Incorporation [45]2 years ago

7 0

Answer:

I guess this answer is c

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2 years ago

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Identify the double displacement reaction. 3Pb 2h 3PO 4 ⟶ 3H 2 Pb 3(PO 4) 2 2NO 2 ⟶ 2O 2 N 2 2NaBr Ca(OH) 2 ⟶ CaBr 2 2NaOH 2NH 3

IRISSAK [1]

Reaction 3 is the double displacement reaction.

Double displacement reaction occurs when the negatively and the positively charged ions of the compounds interchange their position when the new compound in the product is formed.

<h3>Which is a double displacement reaction?</h3>

In the first reaction, the element lead (Pb) is not an ion and no exchange of the cations or the anions occurs hence it is not a double displacement reaction.

In the second reaction, one compound is getting split into two new compounds and is a decomposition reaction.

In the third reaction, $\rm Br^{-}$ in $\rm 2NaBr$ and $\rm (OH)_{2}$ in $\rm Ca(OH)_{2}$ are anions and cations and exchanges their places to produce two new compounds $\rm CaBr_{2} + 2NaOH.$

In the fourth reaction, a single compound is generated as the result of the combination reaction and hence, it is not the double displacement reaction.

Therefore, $\rm 2NaBr + Ca(OH)_{2} \rightarrow CaBr_{2} + 2NaOH$ is the double displacement reaction.

Learn more about double displacement reaction here:

brainly.com/question/10091171

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1 year ago

In 1787,_________discovered a relationship between charge, their separation, and the force between the two charges. A coulomb B

masya89 [10]

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2 years ago

In an acid-base neutralization reaction 38.74 ml of 0.500 m potassium hydroxide reacts with 50.00 ml of sulfuric acid solution.

DaniilM [7]

Answer:

0.2 M.

Explanation:

For the acid-base neutralization, we have the role:

The no. of millimoles of acid is equal to that of the base at the neutralization.

∴ (XMV) KOH = (XMV) H₂SO₄.

X is the no. of reproducible H⁺ (for acid) or OH⁻ (for base),

M is the molarity.

V is the volume.

For KOH:

X = 1, M = 0.5 M, V = 38.74 mL.

For H₂SO₄:

X = 2, M = ??? M, V = 50.0 mL.

∴ M of H₂SO₄ = (XMV) KOH/(XV) H₂SO₄ = (1)(0.5 M)(38.74 mL)/(2)(50.0 mL) = 0.1937 M ≅ 0.2 M.

5 0

2 years ago