Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Yes oh is it for a new pfp year anniversary of thanksgiving day at the same time and i dont
Answer:
Step-by-step explanation:
distributive
Given-
Cost of milk 4 years ago = £1.05
To find-
Percentage increase in cost
Solution-
Increase in cost = £ ( 1.26 - 1.05 )
→ £ 0.21
Percentage increase :-
Therefore, Percentage increase of the cost of milk over 4 years is <u>2</u><u>0</u><u>%</u> .
✍️ <em>By </em><em>Benjemin</em> ☺️
