The figure is missing so I attached a helping figure
Answer:
Line segment ST is congruent to line segment UT
Step-by-step explanation:
From the attached figure
∵ ST and UT are tangents to circle K at points S and U
∵ SK and UK are radii in the circle K
- The tangent is perpendicular to the radius at the point of tangent
∴ ST ⊥ KS ⇒ at point S
∴ m∠KST = 90°
∴ UT ⊥ KU ⇒ at point U
∴ m∠KUT = 90°
∴ m∠KST = m∠KUT
In the two triangles KST and KUT
∵ KS = KU ⇒ radii
∵ m∠KST = m∠KUT ⇒ proved
∵ KT is a common side in the two triangles
- That means the two triangles are congruent by HL postulate
of congruence (hypotenuse and leg of right triangle)
∴ Δ KST ≅ KUT ⇒ HL postulate of congruence
- By using the result of congruence
∴ ST = UT
Line segment ST is congruent to line segment UT
The answer to question number 1 is 16.
Given:
2 ft³ of clay was mixed into 7 ft³ of soil containing 55% clay.
To find:
Clay content of the mixture.
Solution:
We have,
55% of soil is clay. So,
Clay in soil= 55% of soil
2 ft³ of clay was mixed into the soil. So, the total clay content of the mixture is
Therefore, the clay continent in the mixture is 5.85 ft³.
Answer:
Step-by-step explanation:
Perimeter = 2*(length +width)
P = 2*( x+8 + y-1)
P = 2*(x + y + 7)
P =2x + 2y + 17
Answer:
41°
Step-by-step explanation:
The angle addition theorem tells you ...
m∠MNR + m∠RNP = m∠MNP
Filling in the given values, you have ...
43° + m∠RNP = 84°
Subtract 43° from both sides of the equation to find the angle of interest:
m∠RNP = 84° - 43° = 41°
The measure of angle RNP is 41°.