What is the amount of heat absorbed when the temperature of 75 grams of water increases from 20 to 75
2 answers:
Answer:
55°C
Explanation:
original is 20
after gaining heat is 75
75 - 20 = 55
Answer:
17242,5J
Explanation:
Given parameters:
Mass of water = 75g
Initial temperature = 20°C
Final temperature = 75°C
Unknown:
Amount of heat absorbed = ?
Solution
To find the amount of heat absorbed by water;
H = mcΔt
m is the mass
c is the specific heat capacity of water = 4.18J/g°C
Insert the parameters and solve;
H = 75 x 4.18 x (75 - 20)
H = 17242,5J
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Answer:
The correct answer will be "18.25 g".
Explanation:
The given values are:
Specific heat,
C = 0.45 J/g･°C
Heat involved,
q = 801 J
Temperature,
ΔT = 120.0°C-22.5°C
= 97.5°C
As we know,
⇒ 
On substituting the given values, we get
⇒ 
⇒ 
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Answer:
D.
Explanation:
An Arrhenius acid is a compound that increases the H+ ion concentration in a water solution.
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