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2 years ago

11

You have discovered an element that is a poor conductor of electricity, has a low melting point, and is a gas at room temperatur

e. How would you classify this element?
A.metal

B.metalloid

C.actinoid

D.nonmetal

1 answer:

NeX [460]2 years ago

6 0

AHHH ITS B SORRY I ACTUALLY KNOE THIS

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TEA [102]

for the first one it is B OR THE SECOND OPTION

8 0

2 years ago

In an effort to try winning World War I, many countries broke previously created treaties and pacts that banned the use of chemi

nadya68 [22]

D the belguim people atacked using it

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3 years ago

Write the molecular formula for a compound with the possible elements C, H, N and O that exhibits a molecular ion at M

liberstina [14]

Answer:

$= \mathbf{C_3H_6O}$

Explanation:

From the given information, since the molecular mass of the ion M+ is not given;

Let's assume M+ = 58.0423

So, by applying the 13th rule;

we will need to divide the mass by 13, after dividing it;

The quotient n = no. of carbon; &

The addition of the quotient (n) with the remainder r = no. of hydrogen.

So;

$\dfrac{58}{13}= 4 \ remainder \ 6$

So;

$C_nH_{n+r} = C_4H_{4+6}$

$= C_4H_{10}$

From the given information; we have oxygen present, so since the mass of oxygen = 16, we put oxygen in the molecular formula by removing $CH_4$ . Also, since the mass is an even number then Nitrogen is 0.

So, we have:

$= \mathbf{C_3H_6O}$

6 0

2 years ago

1. Multiple Choice

solong [7]

Answer:

#1 A

#2 B

#3 C

#4 c

Explanation:

#1 can give reference to a mountain the higher the altitude the colder it will get

#2 talking about climate not seasons per say. focus on climate answers

#3 wind carry moisture from the sea on to land which cause precipitation

#4 Monsoons is correct

5 0

2 years ago

Calculate the value of the equilibrium constant, Kc, for the reaction below, if 0.208 moles of sulfur dioxide gas, 0.208 moles o

Harman [31]

First, we convert the moles of each substance into the concentration using the volume of the reactor.
[SO₃] = 0.425/1.5 = 0.283 M
[SO₂] = 0.208 / 1.5 = 0.139 M
[O₂] = 0.208/1.5 = 0.139 M
The equilibrium constant is calculated by:
Kc = [SO₃]² / [O₂][SO₂]²
Kc = (0.283)²/(0.139)(0.139)²
Kc = 29.8 = 2.98 x 10¹

The answer is C

8 0

2 years ago