Answer:
Step-by-step explanation:
Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m
Dimensions of a small locker are 0.5 m × 0.6 m × 
(as height of small locker is half the height of big locker )
To find: total volume of one big locker and one small locker
Solution:
Volume of cuboid = length × breadth × height
Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker
= 
Answer:
21 Students
Step-by-step explanation:
140 x .15 = 21
Hypotenuse ^2 = base^2 + perpendicular ^2
H^2 = 6^2 + 8^2
H^2 = 36 + 64
H^2 = 100
H = 10
(This is a right angle triangle as 60+30= 90
180-90= 90)
Answer:
The large container holds 6 cups of water
Step-by-step explanation:
If two small containers and one large container equal 10 cups and one large minus one small equals 4 cups then that means that each small container has to equal 2 cups of water.
Hi there.
Y = 2x + 3
Solve for y when x = 3
The first thing we need to do is replace x by the 3 in the equation.
Y = 2(3) + 3
Y = 6 + 3
Y = 9
Thus, your answer is : C
